Step-by-step explanation:
do u have like a photo or sum to explain it better
<span>If you plug in 0, you get the indeterminate form 0/0. You can, therefore, apply L'Hopital's Rule to get the limit as h approaches 0 of e^(2+h),
which is just e^2.
</span><span><span><span>[e^(<span>2+h) </span></span>− <span>e^2]/</span></span>h </span>= [<span><span><span>e^2</span>(<span>e^h</span>−1)]/</span>h
</span><span>so in the limit, as h goes to 0, you'll notice that the numerator and denominator each go to zero (e^h goes to 1, and so e^h-1 goes to zero). This means the form is 'indeterminate' (here, 0/0), so we may use L'Hoptial's rule:
</span><span>
=<span>e^2</span></span>
29/48 is about 60 percent to the nearest hundredth
Answer:
-25
Step-by-step explanation:
Essentially, y is your output and x is your input.
Here's your base equation: y = 2x + 5
Knowing the information above, let's plug it in:
-45 = 2x + 5
(Subtract 5 from both sides)
-50 = 2x
(Divide both sides by 2 to isolate x)
-25 = x
And there you go.
