(x+2)^4=((x+2)^2)^2(x+2)^2=(x^2+2^2+2(x)(2))= x^2+4+4x (x^2+4+4x)^2=(x^2+4+4x)(x^2+4+4x) = x^4+4x^2+4x^3+4x^2+16+16x+4x^3+16x+16x^2=x^4+4x^3+4x^3+4x^2+16x^2+4x^2+16x+16x+16=x^4+8x^3+24x^232x+16
The question is incomplete :
The height, width and Lenght isn't Given. However, we can create an hypothetical scenario, with a height 6, length 8 and width 4
Answer:
192 unit³
Step-by-step explanation:
The volume of the card box :
Recall the volume of box formula :
V = length * width * height
Volume = 8 * 6 * 4
Volume = 192 unit³
This is the procedure for any given dimension of the card deck.
70,000 when a zero is in between you gonna count it
4 sides. Think of a trapezoid like a drunk rectangle.
-Hope this helps!
Answer: a) -13/16
Step-by-step explanation: Start by setting equations equal and rearrange X^3 - x^2 + 1 = 0. Visual inspection of graph shows x between -1 and -1/2. Start with x = 3/4 plug in and calculate: just a little too small. Try going halfway towards -1: x =-7/8 Plug in and the answer is very far from 0. Go halfway back towards -3/4: -13/16 and the equality is very close.
