What is the range o the function h(x)=-8^x

2 answers:

8 0

the answer is the first one y<0

4 0

The range of the function h(x)=-8^x is:

C. y<-1

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Vesna [10]

Answer:

It's 4-12x

Step-by-step explanation:

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Elina [12.6K]

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ASHA 777 [7]

$\bf \sqrt{x^{16}y^2}\implies \sqrt[2]{x^{8\cdot 2}y^2}\implies \sqrt[2]{(x^8)^2y^2}\implies x^8y$

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diamong [38]

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Marysya12 [62]

Answer:

x= 54.09

Step-by-step explanation:

cos = adjacent/ hypotenuse

cos75 = 14/x

x = 14/cos75

x = 54.09814627

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2 years ago