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valkas [14]
3 years ago
11

(Q10) It's a long question so I will give you 30 points for answering it. Thank You!

Mathematics
1 answer:
Rasek [7]3 years ago
4 0

Answer:

  c. 30.9 °C; 32.9 °C

Step-by-step explanation:

Put the given numbers into the given formula and do the arithmetic.

(a) The temperature of sample 1 is ...

  y = (100 -24)e^(-0.12·20) + 24 ≈ 30.9

___

(b) The temperature of sample 2 is ...

  y = (100 -4)e^(-0.12·10) +4 ≈ 32.9

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3 years ago
A bicycle tire has a diameter of 62 cm
anzhelika [568]

Answer

1946.8 cm

Step-by-step explanation:

you first need to find the circumference of the tire. to do this you use the formula C=d(3.14)

you plug in the 62 to the d

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4 years ago
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Step-by-step explanation:

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3 years ago
An orchard has 667 orange trees. The number of rows exceeds the number of trees per row by 6. How many trees are there in each r
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Step-by-step explanation:

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3 years ago
The half-life of Radium-226 is 1590 years. If a sample contains 400 mg, how many mg will remain after 2000 years?
Assoli18 [71]

Answer:

167.27 mg.

Step-by-step explanation:

We have been given that the half-life of Radium-226 is 1590 years and a sample contains 400 mg.

We will use half life formula to solve our given problem.

N(t)=N_0*(\frac{1}{2})^{\frac{t}{t/2}, where N(t)= Final amount after t years, N_0= Original amount, t/2= half life in years.

Now let us substitute our given values in half-life formula.

N(2000)=400*(\frac{1}{2})^{\frac{2000}{1590}

N(2000)=400*(0.5)^{1.2578616352201258}    

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N(2000)=167.26532115499512956\approx 167.27

Therefore, the remaining amount of Radium-226 after 2000 years will be 167.27 mg.

3 0
3 years ago
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