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ladessa [460]
3 years ago
6

What do I do? Help me please I'm stuck

Mathematics
1 answer:
Komok [63]3 years ago
3 0
9/8 or 1 1/8
Yw and, make sure not to report and to do give me brainliest
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In triangle ABC, a=7, b=3 and cos C = 1/2. The value of c is
aalyn [17]

Answer:

Correct option: 2 -> sqrt(37)

Step-by-step explanation:

To solve this problem, we just need to use the law of cosines. This law is used to find the third side of a triangle, when we have the two other sides and the angle between them.

The equation of the law of cosines is:

c^2 = a^2 + b^2 - 2 * a * b * cos(C)

So, we have that:

c^2 = 7^2 + 3^2 - 2 * 7 * 3 * (1/2)

c^2 = 49 + 9 - 21

c^2 = 37

c = sqrt(37)

Correct option: 2

8 0
3 years ago
Find the other endpoint of the line segment with the given endpoint and midpoint. Endpoint: (-2, -6) Midpoint: (-5, 1)
FromTheMoon [43]

Answer:

(-8,8)

Step-by-step explanation:

The midpoint M(x_M,y_M) of the segment AB with endpoints A(x_A,y_A) and B(x_B,y_B) has coordinates

x_M=\dfrac{x_A+x_B}{2}\\ \\y_M=\dfrac{y_A+y_B}{2}

In your case, A(-2,-6), \ M(-5,1), then

-5=\dfrac{-2+x_B}{2}\Rightarrow -2+x_B=-10,\ x_B=-10+2=-8\\ \\1=\dfrac{-6+y_B}{2}\Rightarrow -6+y_B=2,\ y_B=2+6=8

3 0
3 years ago
If / and / are midsegments of , what can you conclude about / and /? Verify your results by finding x when QR = 3x + 2 and NP =
Ad libitum [116K]
Midsegments are line segments that connect the midpoints of a triangle. If we have the condition that QR = NP, we have the equation
3x + 2 = 2x + 16
Solving for x
3x - 2x = 16 - 2
x = 14
Therefore, x is 14. <span />
8 0
3 years ago
A deli sells sliced meat and cheese. One customer purchases 4 pounds of meat and 5 pounds of cheese for a total of $30.50. A san
Elenna [48]

Answer:x=cost per pound of meat

Y=Cost per pound of cheese

The deli charges 4.50 for a pound of meat

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
I need help getting the answer could you help me by chance to receive brainlest!?
Pani-rosa [81]
(Placeholder because it won’t let me ask more questions until I answer some)
5 0
3 years ago
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