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2 years ago

Dividir entre la raíz más cercana

Mathematics

1 answer:

inna [77]2 years ago

7 0

Where is the question ?

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What is place value of 2 in 72,389

vfiekz [6]

2,000
hope I could help you out :]

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4 years ago

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When I double my number and add eight , I get my number plus twelve. What is my number?

Butoxors [25]

Your answer is 2 as if you double 2 you get 4 and add 8 oh get 12

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3 years ago

On your last math test you earned an 88%. Of the 26 questions on the test, how many did you get correct?

dybincka [34]

Answer:

i belive the answer is 23

Step-by-step explanation:

You just have to divide then multiple by 100

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3 years ago

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Rewrite the statement in mathematical notation. (Let y be the distance from the top of the ladder to the floor, x be the distanc

In-s [12.5K]

Answer:

$\frac{dy}{dt}=\frac{6y}{x}\text{ ft per sec}$

Step-by-step explanation:

Let L be the length of the ladder,

Given,

x = the distance from the base of the ladder to the wall, and t be time.

y = distance from the base of the ladder to the wall,

So, by the Pythagoras theorem,

$L^2 = y^2 + x^2$

$\implies L = \sqrt{y^2 + x^2}$ ,

Differentiating with respect to time (t),

$\frac{dL}{dt}=\frac{d}{dt}(\sqrt{x^2 + y^2})$

$=\frac{1}{2\sqrt{x^2 + y^2}}\frac{d}{dt}(x^2 + y^2)$

$=\frac{1}{2\sqrt{x^2 + y^2}}(2x\frac{dx}{dt}+2y\frac{dy}{dt})$

$=\frac{1}{\sqrt{x^2 +y^2}}(x\frac{dx}{dt}+y\frac{dy}{dt})$

Here,

$\frac{dy}{dt}=-6\text{ ft per sec}$

Also, $\frac{dL}{dt} = 0$ ( Ladder length = constant ),

$\implies \frac{1}{\sqrt{x^2 +y^2}}(x(-6)+y\frac{dy}{dt})=0$

$-6x + y\frac{dy}{dt}=0$

$y\frac{dy}{dt}=6x$

$\implies \frac{dy}{dt}=\frac{6y}{x}\text{ ft per sec}$

Which is the required notation.

8 0

3 years ago

The diagram shows. LOOK AT THE PIC.<br>pls help me.

Reptile [31]

Answer:

The perimeter of the shaded region is 267.8 m ( approximately)

Step-by-step explanation:

3 0

3 years ago

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