@ 4x +(2x - 1) = x +5+x-6

Mathematics

2 answers:

fomenos3 years ago

5 0

Answer:

I believe the answer is 4 but im not sure because I skipped the @ but I didnt know what it meant

Step-by-step explanation:

Ugo [173]3 years ago

5 0

4x +(2x - 1) = x +5+x-6

pretend that there is a 1 in front of the bracket

4x+1(2x-1)= x+5+x-6

Mutiply the bracket by 1

(1)(2x)= 2x

(1)(-1)= -1

4x+2x-1=x+x+5-6( combine like terms)

6x-1= 2x-1

move 2x to the other side

sign changes from +2x to -2x

6x-2x-1= 2x-2x-1

4x-1=-1

move -1 to the other side

4x-1+1= -1+1

4x= 0

divide by 4 for both sides to get x by itself

4x/4= 0/4

Cross out 4 and 4, divide by 4 and then becomes 1*1*x= x

x= 0/4

Answer: x= 0

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The figure shows △XYZ. XW⎯⎯⎯⎯⎯⎯ is the angle bisector of ∠YXZ .<br><br> What is WZ ?

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Use the law of cosines to find the measure of angle YXZ.

$8^2=6.5^2+6^2-2(6.5)(6)\cos(\angle YXZ)$
$\cos(\angle YXZ)\approx0.1827$
$\angle YXZ\approx 1.3871\text{ rad}\approx79.4734^\circ$

This means angles YXW and WXZ share the same measure of about $39.7367^\circ$ .

Use the law of cosines again to find the measure of angle XZW.

$6.5^2=8^2+6^2-2(8)(6)\cos(\angle XZW)$
$\cos(\angle XZW)\approx0.6016$
$\angle XZW\approx0.9253\text{ rad}\approx53.0181^\circ$

This means the measure of angle XWZ is

$180^\circ=\angle WXZ+\angle XWZ+\angle XZW\implies \angle XWZ\approx87.25^\circ$

Now using the law of sines, you have

$\dfrac{\sin(\angle WXZ)}{WZ}=\dfrac{\sin(\angle XWZ)}6\implies WZ\approx3.84$