We either need to see a picture of this and/or get more information about the measurements of the triangle. In general, the area outside of the triangle will be the area of the semi-circle minus the area of the triangle itself, or: 1/2*49*3.14 - 1/2 b*h of the triangle. That first part, which is the area of the semi-circle, works out to 76.93 So based on the info we have, it becomes 76.93 - 1/2*b*h of the triangle = area outside of triangle.
Answer:

Step-by-step explanation:
The equation of the slope of the tangent line L is obtained by deriving the equation of the hyperbola:


The numerical value of the slope is:

The component of the y-axis is:

Now, the tangent line has the following mathematical model:

The value of the intercept is found by isolating it within the equation and replacing all known variables:


Thus, the tangent line is:

The vertical distance between a point of the tangent line and the origin is given by the intercept.

In order to find horizontal distance between a point of the tangent line and the origin, let equalize y to zero and clear x:




The area of the triangle is computed by this formula:



Answer:
D
Step-by-step explanation:
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