Your answer would be 0.315 because:P(2\ spades)=\frac{13C2\times 39C4}{52C6}=0.315
I think that x=2 and so does y=2. Hope that answers your question.
Well, it might be something like 18x-6 = 78x2?
Have you tried that?
Answer:
201
Step-by-step explanation:
C = 2pi.R
50.24/2pi = R
R= 8
area = pi R² = pi x 8² = 201
Answer:
The first listed equation is the correct equation to solve
The correct answer is: t = 5 seconds
Step-by-step explanation:
Let me mention first that there is an error in the statement that the gravitational pull of the Earth is 16 ft/s^2. It is in fact 32 ft/s^2, and the actual equation uses half of the acceleration multiplied by the square of the variable time, so it gives as final expression :

and we want to find the value/s for "t" that make this equation equal zero (when it reaches the ground and the object just touches the ground. This makes the equation we want to solve:

which solving for "t" becomes:

So we adopt the positive answer (positive time) since the negative value has no physical meaning for this problem.
That is: t = 5 seconds