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4 years ago

Which statement correctly describes the relationship between the graph of f(x) and the graph of g(x)=f(x)-1?

Mathematics

2 answers:

AlladinOne [14]4 years ago

8 0

Answer:

The correct answer is C. because the graphs are the same, save that -1 on the graph of g(x), which moves the graph down 1 unit

Step-by-step explanation:

LiRa [457]4 years ago

3 0

Answer:

Step-by-step explanation:

The - 1 means its a translation of 1 units down.

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PROVE THAT:<br><br>cos 20° - sin 20° = \sqrt{2}sin25°<br><br>

Lemur [1.5K]

Answer:

See below.

Step-by-step explanation:

$\cos(20)-\sin(20)=\sqrt{2}\sin(25)$

First, use the co-function identity:

$\sin(90-x)=\cos(x)$

We can turn the second term into cosine:

$\sin(20)=\sin(90-70)=\cos(70)$

Substitute:

$\cos(20)-\cos(70)=\sqrt{2}\sin(25)$

Now, use the sum to product formulas. We will use the following:

$\cos(x)-\cos(y)=-2\sin(\frac{x+y}{2})\sin(\frac{x-y}{2})$

Substitute:

$\cos(20)-\cos(70)=-2\sin(\frac{20+70}{2})\sin(\frac{20-70}{2})\\\cos(20)-\cos(70) =-2\sin(45)\sin(-25)\\\cos(20)-\cos(70)=-2(\frac{\sqrt{2}}{2})\sin(-25)\\ \cos(20)-\cos(70)=-\sqrt{2}\sin(-25)$

Use the even-odd identity:

$\sin(-x)=-\sin(x)$

Therefore:

$\cos(20)-\cos(70)=-\sqrt{2}\sin(-25)\\\cos(20)-\cos(70)=-\sqrt{2}\cdot-\sin(25)\\\cos(20)-\cos(70)=\sqrt{2}\sin(25)$

Replace the second term with the original term:

$\cos(20)-\sin(20)=\sqrt{2}\sin(25)$

Proof complete.

4 0

4 years ago

9/8*0.97 which is closer to a.0.5 b.1 c.2

Vsevolod [243]

9/8 * 0.97 is equal to 1.09 so it would be closer to B. 1

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3 years ago

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Andre45 [30]

The answer to your question would be 4 miles an hour

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Nonamiya [84]

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Substitute:

$y-2=\dfrac{1}{2}(x-(-8))\\\\\boxed{y-2=\dfrac{1}{2}(x+8)}$

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3 years ago

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Misha Larkins [42]

Answer:

Step-by-step explanation:

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3 years ago