Total investment = $10,500
Let x = amount of first investment, and y the amount of the second investment.
First investment:
Interest rate = 9 (1/5)% = 0.092
Earned interest = 0.092x
Second investment:
Interest rate = 9% = 0.09
Earned interest = 0.09y
Total interest after one year is $957.00, therefore
0.092x + 0.09y = 957
or
1.0222x + y = 10633.33 (1)
Also,
x + y = 10500 (2)
Subtract (2) from (1).
0.0222x = 133.33
x = 6000
y = 10500 - x = 4500
Answer:
The first investment is $6,000 at 9 (1/5)% rate;
The second investment is $4,500 at 9% rate.
So if 199.75 is the cost after a 18% discount
The original price is 100%
Then the price after a 18% discount is
Tell me as a percentage
Answer:
23) 36·(3·1/4) = 36·(3/4) = 108/4 = 27
24) (4·2/7)·21 = (8/7)·21 = 168/7 = 24
25) 2(x+4) = 2x+8
26) (5+n)3 = 15+3n
27) (4-3m)8 = 32-24m
28) -3(2x-6) = -6x+18
29) 13r+5r = 18r
30) 3x³-2x²
31) 7m+7-5m = 2m+7
32) 5z²+3z+8z² = 3z+13z²
33) (2-4n)17 = 34-68n
34) 11(4d+6) = 44d+66
35) 7m+2m+5p+4m = 13m+5p
36) 3x+7(3x+4) = 3x+21x+28 = 24x+28
37) 4(fg+3g)+5g = 4fg+12g+5g = 4fg+17g
38) (5m)²+(m+5)²= 26m²+10m+25
39) 7(a²+b)-4(a²+b) = 3(a²+b) = 3a²+b
Answer:
a: 1037 is the minimum sample size needed
b: 712 is the minimum sample size needed
Step-by-step explanation:
We need to use the formula for minimum sample size of a proportion when a sample proportion is known.
The level of confidence is 99%, which has a corresponding z-value of 2.575.
We know the desired error is 4%, or 0.04.
Part a: We have no prior estimate. See attached photo for calculation
Part b:
We know p-hat = 0.22. Therefore q-hat = 1 - 0.22 = 0.78
See the attached photo for the calculation of the minimum sample size
