63 5 tens=50
13 ones=10 and 3 leftover 50+13=63
Its B. it would be impossible to be D, because a positive plus a positive cannot be a negative. but a Negative plus a positive would equal a negative. so B is correct
Answer:
Yes, the zeros should be counted as significant.
Step-by-step explanation:
The zeros are significant because they show the place value of the number that is being rounded so they show how big the number is.
Answer:
6x-7y=17-----y=6/7x-17/7
6x-11y=-13----y=6/11x-13/11
6x-11y=13----y=6/11x+13/11
11x-6y=13-----y=11/6x-13/6
Step-by-step explanation:
The answer would be 4^9-5 or 262139