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Galina-37 [17]
3 years ago
11

How far away is a star with a parallax of 2 arc sec in parsecs? In AU?

Mathematics
1 answer:
Vesna [10]3 years ago
8 0

Answer:

ear

Step-by-step explanation:

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Graph a system of equations to approximate the
SIZIF [17.4K]

Answer: B

Step-by-step explanation:

8 0
2 years ago
Graph the solution of 2 ≥ 4 - v
Lerok [7]
For this case we have the following inequality:
 2 ≥ 4 - v
 The first thing we must do in this case is to clear the value of v.
 We have then:
 v ≥ 4 - 2
 v ≥ 2
 Therefore, the solution set is given by:
 [2, inf)
 Answer:
 
See attached image.

6 0
2 years ago
Read 2 more answers
Will give brainliest!
Gala2k [10]
Check the picture below, it hits the ground when y = 0.

\bf ~~~~~~\textit{initial velocity}\\\\
\begin{array}{llll}
~~~~~~\textit{in feet}\\\\
h(t) = -16t^2+v_ot+h_o \\\\
\end{array} 
\quad 
\begin{cases}
v_o=\stackrel{0}{\textit{initial velocity of the object}}\\\\
h_o=\stackrel{162}{\textit{initial height of the object}}\\\\
h=\stackrel{}{\textit{height of the object at "t" seconds}}
\end{cases}
\\\\\\
h(t)=-16t^2+0t+162\implies 0=-16t^2+162\implies 16t^2=162
\\\\\\
t=\cfrac{162}{16}\implies t=\cfrac{81}{8}\implies t=10\frac{1}{8}

6 0
2 years ago
Solve the equation by completing the square root round to the nearest hundredth if necessary X^2+3x=24
marysya [2.9K]
X^2 + 3x = 24

completing the square
(x + 1.5)^2 - 2.25 = 24

(x + 1.5)^2 = 26.25

x + 1.5  = +/- sqrt26.25 =  +- 5.123

x = -1.5 + 5.123 = 3.62 to nearest hundredth  and

x =  -1.5 - 5.123  =   -6.62 to nearest hundredth

solution set is {-6.62, 3.62}
7 0
3 years ago
Read 2 more answers
Of the 200 students surveyed at the local high school, 126 say that they prefer earlier start times for school. What is the mean
ra1l [238]

Answer:

The mean of sampling distribution of the proportion of the students who prefer later start times for school

                        μₓ = p = 0.63

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given sample size 'n' =200

given data Of the 200 students surveyed at the local high school, 126 say that they prefer earlier start times for school

sample proportion

                        p = \frac{x}{n} = \frac{126}{200} = 0.63

The mean of sampling distribution of the proportion of the students who prefer later start times for school

                        μₓ = p = 0.63

Standard deviation of the proportion

                     S.D = \sqrt{\frac{p(1-p)}{n} } = \sqrt{\frac{0.63(1-0.63)}{200} } = 0.034

5 0
3 years ago
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