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2 years ago

HELP ME PLEASE!!!!! IM DYING WITH ALL THIS MATH HW

Mathematics

2 answers:

sashaice [31]2 years ago

7 0

Nxjdkdnc knockzjznsbdbxbzmzmmd xbxidnrnfu. Xizneshzudnd check x

trasher [3.6K]2 years ago

5 0

3x=129 , x =43 distribute 3 to get x by itself

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Shannon is selling boxes cookies and candy for a fundraiser. She's sold each box of cookies for $5.25. She also sold one one box

defon

Answer:

The minimum boxes of cookies is 39

Step-by-step explanation:

Let

x ----> the number of boxes of cookies sold

y ----> the number of boxes of candies sold

we know that

The word "at least" means "greater than or equal to"

The inequality that represent this problem is

$5.25x+8.75y\geq 200$

The solution is the shaded area above the solid line $5.25x+8.75y=200$

using a graphing tool

The solution is the shaded area -----> see the attached figure

Find out the minimum boxes of cookies needed to sell to reach the goal

assuming only cookies are sold

For y=0

$5.25x+8.75(0)\geq 200$

$5.25x\geq 200$

solve for x

$x\geq 38.1$

Round up

therefore

The minimum boxes of cookies is 39

5 0

2 years ago

In circle P, EG and FH are diameters. What is m EH?

zvonat [6]

Answer:

$m(\widehat{EH})$ = 130°

Step-by-step explanation:

Angles subtended at the center by the arcs $(\widehat{HG})$ and $(\widehat{EF})$ are ∠HPG and ∠EPF.

Since these angles are the vertical angles both will be equal.

m∠HPG ≅ m∠EPF

3x - 10 = 2x + 10

3x - 2x = 10 + 10

x = 20

Therefore, $m(\widehat{HG})=(3\times 20) - 10$

= 50°

Similarly $m(\widehat{EF})$ = 50°

In the same way angles subtended at the center will be equal.

m∠EPH ≅ m∠FPG

and $m(\widehat{EH})=m(\widehat{FG})$

Since $m(\widehat{EH})+m(\widehat{FG})+m(\widehat{EF})+m(\widehat{HG})=360$ °

$m(\widehat{EH})+m(\widehat{EH})+50+50=360$

$2m(\widehat{EH})=360-100$

$m(\widehat{EH})=130$

Therefore, measure of arc EH = 130°

3 0

3 years ago

A rectangular prism has a length of 7 inches and a width of 5 inches. The lateral area is 192 square inches. What is the height

Dennis_Churaev [7]

Answer:

I think it would be 5.49 as the height of the prism.

Step-by-step explanation:

I just did 7 × 5 which is 35, and then I did 192 ÷ 35 and got 5.49. I'm not completely sure but that's my best answer I hope it helps!

6 0

2 years ago

Read 2 more answers

What graph matches y=-3x-2

Naya [18.7K]

Answer:

There is no picture dude

Step-by-step explanation:

8 0

2 years ago

1. The scale of a map is 1 in = 19.5 mi map: ________ in actual: 9.5 mi 2. The scale of a map is 7 in = 16 mi map: 4.9 in actual

alexandr402 [8]

We use ratio and proportion to solve each of these:

1. The scale of a map is 1 in = 19.5 mi map: ________ in actual: 9.5 mi
1 in / 19.5 mi = x in / 9.5 mi, x = 0.487 in

2. The scale of a map is 7 in = 16 mi map: 4.9 in actual: ______ mi
7 in / 16 mi = 4.9 in / x mi, x = 11.2 mi

3. The scale factor for a model is 5 cm = ________ m Model : 72.5 cm actual: 165.3 m
5 cm / x m = 72.5 cm / 165.3 m, x = 11.4 m

4. The scale of a map is 1 in = 9.6 mi map: ________ in actual: 34.7 mi
1 in / 9.6 mi = x in / 34.7 mi, x = 3.62 in

5. The scale of a map is 1 ft = 9.6 mi map: ________ ft actual: 38.4 mi
1 ft / 9.6 mi = x ft / 38.4 mi, x = 4 ft

6. The scale factor for a model is 5 cm = ________ m Model : 22.4 cm actual: 155.2 m
5 cm / x m = 22.4 cm / 155.2 m, x = 34.64 m

7. The scale of a map is 5 in = 10 mi map: 8.7 in actual: ______ mi
5 in / 10 mi = 8.7 in / x mi, x = 17.4 mi

8. The scale of a map is 1 in = 13.5 mi map: ________ in actual: 65.9 mi
1 in / 13.5 mi = x in / 65.9 mi, x = 4.88 in

9. The scale factor for a model is 5 cm = ________ m Model : 61.5 cm actual: 143.2 m
5 cm / x m = 61.5 / 143.2 m, x = 11.64 m

10. The scale factor for a model is 5 cm = ________ m Model : 29.7 cm actual: 179.5 m
5 cm / x m = 29.7 cm / 179.5 m, x = 30.22 m

3 0

3 years ago