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levacccp [35]
3 years ago
13

What is the y-intercept of f–1(x)?

Mathematics
1 answer:
wolverine [178]3 years ago
8 0

Answer:

-16

Step-by-step explanation:

The given linear function is ; f(x)=\frac{3}{4}x+12

Let y=\frac{3}{4}x+12.

We interchange x and y.

x=\frac{3}{4}y+12.

We solve for y.

x-12=\frac{3}{4}y.

We now multiply through by \frac{4}{3} to get:

\frac{4}{3}x-12\times\frac{4}{3}=y.

This simplifies to;

y=\frac{4}{3}x-16.

Hence f^{-1}(x)=\frac{4}{3}x-16.

The y-intercept is -16

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1) Use power series to find the series solution to the differential equation y'+2y = 0 PLEASE SHOW ALL YOUR WORK, OR RISK LOSING
iogann1982 [59]

If

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y'=\displaystyle\sum_{n=1}^\infty na_nx^{n-1}=\sum_{n=0}^\infty(n+1)a_{n+1}x^n

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\displaystyle\sum_{n=0}^\infty(n+1)a_{n+1}x^n+2\sum_{n=0}^\infty a_nx^n=0

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We can solve the recurrence exactly by substitution:

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