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xeze [42]
3 years ago
11

The daily recommended allowance of vitamin C for a sixth grader is 45 mg. 1 orange has about 75% of the recommended daily allowa

nce of vitamin C. How many milligrams are in 1 orange?
Mathematics
1 answer:
Elden [556K]3 years ago
3 0

Answer:

  about 33.75 mg

Step-by-step explanation:

75% of 45 mg is ...

  0.75 × 45 mg = 33.75 mg

About 33.75 mg of vitamin C are in one orange.

__

You might be asked to round this to 34 mg.

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Step-by-step explanation:

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74ft <br> 24ft <br> b<br> What is the length of the missing leg?
amm1812

Answer: 70

Step-by-step explanation:

a^2 + b^2 = c^2

24^2 + b^2 = 74^2

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4 0
2 years ago
Write the integral that gives the length of the curve y = f (x) = ∫0 to 4.5x sin t dt on the interval ​[0,π​].
Troyanec [42]

Answer:

Arc length =\int_0^{\pi} \sqrt{1+[(4.5sin(4.5x))]^2}\ dx

Arc length =9.75053

Step-by-step explanation:

The arc length of the curve is given by \int_a^b \sqrt{1+[f'(x)]^2}\ dx

Here, f(x)=\int_0^{4.5x}sin(t) \ dt interval [0, \pi]

Now, f'(x)=\frac{\mathrm{d} }{\mathrm{d} x} \int_0^{4.5x}sin(t) \ dt

f'(x)=\frac{\mathrm{d} }{\mathrm{d} x}\left ( [-cos(t)]_0^{4.5x} \right )

f'(x)=\frac{\mathrm{d} }{\mathrm{d} x}\left ( -cos(4.5x)+1 \right )

f'(x)=4.5sin(4.5x)

Now, the arc length is \int_0^{\pi} \sqrt{1+[f'(x)]^2}\ dx

\int_0^{\pi} \sqrt{1+[(4.5sin(4.5x))]^2}\ dx

After solving, Arc length =9.75053

5 0
3 years ago
The distance a cargo ship travels is proportional to time. In 2 hours, the ship travels 53 miles. The relationship between dista
frutty [35]

Answer:26

Step-by-step explanation:

The reason i got 26:

-we substitute the letters(variables) and have 52=(k)2

but what is k? k is y divided by x (just like y is k times x)

6 0
3 years ago
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