Question

HELP ME solve for the right triangle

Answer 1

Answer:

see explanation

Step-by-step explanation:

Using the cosine and tangent ratios in the right triangle

cos41° = $\frac{adjacent}{hypotenuse}$ = $\frac{VW}{VX}$ = $\frac{7}{VX}$

Multiply both sides by VX

VX × cos41° = 7 ( divide both sides by cos41° )

VX = $\frac{7}{cos41}$ ≈ 9.3

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tan41° = $\frac{opposite}{adjacent}$ = $\frac{WX}{VW}$ = $\frac{WX}{7}$

Multiply both sides by 7

7 × tan41° = WX, thus

WX ≈ 6.1

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The sum of the 3 angles in a triangle = 180°

Subtract the sum of the given angles from 180° for ∠ X

∠ X = 180° - (90 + 41)° = 180° - 131° = 49°