Answer:
There are no real solutions
Step-by-step explanation:
Recall that for a quadratic equation in the form:
ax² + bx + c = 0
using the quadratic formula, that the discriminant of the formula is given by the following expression
Discriminant = b² - 4ac
If b² - 4ac < 0 ----> No real roots
If b² - 4ac > 0 ----> Two real roots
If b² - 4ac = 0 ----> One real roots
In our case, a = 3, b = -2 and c = 4
b² - 4ac = (-2)² - 4(3)(3) = 4 - 36 = -32 (which is <0)
Hence there are no real roots.
