Answer:
Exactly one solution
Explanation:
The first step we need to take to find the answer is to find the value of y.
7(y+3)=5y+8
Expand the parentheses
7y+21=5y+8
Subtract both sides by 21
7y+21-21=5y+8-21
7y=5y-13
Subtract both sides by 5y
7y-5y=5y-13-5y
2y=-13
Divide both sides by 2
2y/2=-13/2
y=-6.5
Now, we plug y back into the original equation.
7(y+3)=5y+8
7(-6.5+3)=5(-6.5)+8
Expand the parentheses
-45.5+21=-32.5+8
-24.5=-24.5
Because both sides of the equation is equal and the equation is true, we can conclude that the equation has one solution.
I hope this helps!
Answer:
I believe it would be 9 & 10. 9^2 is 81 and 10^2 is 100 which are numbers that fall in between √111.
Step-by-step explanation:
Whenever a problem says "one number" and "another number" we can substitute x and y. for this we have x=2y+1 and xy=1. since we know the value of x (2y+1) we can substitute it for the other equation to get (2y+1)y=10. simplify to get 2y^2+y=10. from here you can do a few methods to solve this, but the simplest in my opinion is by factoring.
In order to factor it must be equal to 0, so we have 2y^2+y-10=0. We factor this and get y=5 (we also get y=-4 but it is an extraneous root). now we can plug that into either equation and find that x=2.
this means our two numbers are 5 and 2
X over 49.5 and 20 over 100 then you cross multiply and you get 100x is equal to 990 you divide 100x and 990 both by 100 and get x and 9.9 then you have 50 seniors a month that you give the discount to so you multiply 9.9 by 50 and get 495 so the total discount you give on an average monthly basis is $495.00 Hope this helped
