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e-lub [12.9K]
3 years ago
14

Lindsay prepared 9 containers of fruit punch for a party. After the party, there were still 4 4/9 containers of fruit punch left

. How many containers were consumed in the party?
Mathematics
1 answer:
umka2103 [35]3 years ago
6 0

Turn 9 into \frac{81}{9}. Then, convert 4 \frac{4}{9} into a improper faction ( \frac{40}{9} ). Then, subtract

\frac{81}{9} - \frac{40}{9} = \frac{41}{9}. Lastly, convert  \frac{41}{9} to a mixed fraction ( 4\frac{4}{9} ).

Your answer is 4\frac{4}{9}.

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How to find the volume of a cone?<br> Height- 8 in.<br> Diameter- 7 in.
mestny [16]
The formula for the volume of a cone is V = \pi r^{2} \frac{h}{3}

So the answer is 102.63
4 0
3 years ago
A drama class has a total of 40 students. The number of males is 6 more than the number of females. How many males and how many
Lady_Fox [76]

Answer:

Females = 17 and males = 23

Step-by-step explanation:

Given that,

Total no of students in the class = 40

Let no. of females = x

No. of males = 6+x

ATQ,

Total students = males + females

40 = x+6+x

40-6 = 2x

34 = 2x

x = 17

Hence, there are 17 females and (6+17= 23) males.

7 0
3 years ago
tank a has 100 gallons of water and is being filled at a rate of 2 gallons per hour. tank b has 140 gallons and is being drained
Artist 52 [7]

Answer:

5 hours must pass

Step-by-step explanation:

Graph the equations y = 2x + 100 and y = -6x + 140

Then find the x intercept of their intersection, in this case, that is 5

5 0
2 years ago
I need help with this question
Lunna [17]
{3,4,5,6} should be the answer
8 0
3 years ago
Given that α and β are the roots of the quadratic equation <img src="https://tex.z-dn.net/?f=2x%5E%7B2%7D%20%2B6x-7%3Dp" id="Tex
siniylev [52]

Answer:

\large \boxed{\sf \ \ \ p=-11 \ \ \ }

Step-by-step explanation:

Hello,

\alpha \text{ and } \beta \text{ are the roots of the following equation}

   2x^2+6x-7=p

It means that

   2\alpha^2+6\alpha-7=p \\\\2\beta ^2+6\beta -7=p \\\\

And we know that

\alpha= 2\cdot \beta

So we got two equations

   2(2\beta)^2+6\cdot 2 \cdot \beta -7=p \\\\8\beta^2+12\beta -7=p\\\\ and \ 2\beta ^2+6\beta -7=p \ So \\\\\\8\beta^2+12\beta -7 = 2\beta ^2+6\beta -7\\\\6\beta^2+6\beta =0\\\\\beta(\beta+1)=0\\\\ \beta =0 \ or \ \beta=-1

For \beta =0, \ \ \alpha =0, \ \ p = -7

For \beta =-1, \ \ \alpha =-2, \ \ p= 2-6-7=-11, \ p=2*4-12-7=-11

I assume that we are after two different roots so the solution for p is p=-11

b) \alpha +2 =-2+2=0 \ and \ \beta+2=-1+2=1

So a quadratic equation with the expected roots  is

x(x-1)=x^2-x

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

3 0
3 years ago
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