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irina [24]
3 years ago
8

Write the expression as a single logarithm with a coefficient of 1. 3 ln x − 8 ln y

Mathematics
1 answer:
viva [34]3 years ago
3 0

Answer:

\ln(\frac{x^3}{y^8})

Step-by-step explanation:

3 \ln(x)-8\ln(y) is the given.

The instructions is to write as a single logarithm.

Let's use the power rule first:

\ln(x^3)-\ln(y^8)

Now we see the minus between the natural logs so we can use the quotient rule:

\ln(\frac{x^3}{y^8})

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Five the equation of line that is perpendicular to f(x)=-2x+1 that goes through point (0,5)
Alinara [238K]

Answer:

y = \frac{1}{2} x + 5

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

f(x) = - 2x + 1 ← is in slope- intercept form

with slope m = - 2

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{-2} = \frac{1}{2} , then

y = \frac{1}{2} x + c

the line crosses the y- axis at (0, 5 ) ⇒ c = 5

y = \frac{1}{2} x + 5 ← equation of perpendicular line

7 0
2 years ago
PLEASE HELP ILL DO ANYTHINGGG
ANEK [815]

Answer:

vertical angles or opposite angles

Step-by-step explanation:

3 0
3 years ago
What is the unit rate of 32 miles per gallon
pishuonlain [190]
The unit rate of 32 is 12
6 0
3 years ago
What’s the answer to this ?
Juli2301 [7.4K]

Answer:

the second one because 3 divided by 1.5 is 2 then it's right

7 0
3 years ago
F(x) = 3 x 2 − 3 x − 6 The domain of a the function f(x) is { -10, -1, 1, 5 }. What is the range of the relation?
jonny [76]

Answer:

{324, 0, -6, 54}

Step-by-step explanation:

Given that F(x) = 3x² − 3 x − 6 If the domain of a the function f(x) is { -10, -1, 1, 5 }.

To get the range, we will find f(x) for all the domains

at x = -10

f(-10) = 3(-10)²-3(-10) - 6

f(-10) = 3(100)-3(-10) - 6

f(-10) = 300+30-6

f(-10) = 330-6

f(-10) = 324

at x = -1

f(-1) = 3(-1)²-3(-1) - 6

f(-1) = 3(1)-3(-1) - 6

f(-1) = 3+3-6

f(-1) = 6-6

f(-1) = 0

at x = 1

f(1) = 3(1)²-3(1) - 6

f(1) = 3(1)-3(1) - 6

f(1) = 3-3-6

f(1) = 0-6

f(1) = -6

at x = 5

f(5) = 3(5)²-3(5) - 6

f(5) = 3(25)-3(5) - 6

f(5) = 75-15-6

f(5) = 60-6

f(5) = 54

Hence the range of the relation are {324, 0, -6, 54}

5 0
3 years ago
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