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Ivahew [28]
3 years ago
13

Can somebody plz answer these 3 questions correct!!! Help (WILL MARK BRAINLIEST

Mathematics
2 answers:
Marianna [84]3 years ago
6 0
6, 9, then 18. Just add 3 every time because it is asking how much it increases. For the first one you multiply it by 2 (2h) which got 6, for the second you multiply it by 3 (3h), and for the last one you multiply it by 6 (6h) which got 18.
LiRa [457]3 years ago
5 0

<em>it increases 3° each hour</em>

3*2= 6

6° after 2 hours

3*3= 9

9° after 3 hours

3*6= 18

18° after 6 hours

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A house is worth 125,000 when it is 2 years old and 135,150 when it is 7 years old. According to this model, how much will the h
kicyunya [14]

Answer:111650

Step-by-step explanation:i think its right

4 0
3 years ago
Please help, will give brainliest to first
Lelechka [254]

Answer:

AN = 16 units

Step-by-step explanation:

So we can use the fact that \frac{AN}{FN} =\frac{OR}{FR}

  • Since this is an isosceles triangle, segments FO and FR are both equal to 7

Manipulating the equation above to solve for AN we have AN = \frac{(FN)(OR)}{FR}

  • Substituting in the known values we have AN=\frac{(10)(11.2)}{7} =16

8 0
3 years ago
Read 2 more answers
Help me find the mean mode range median
pashok25 [27]

Answer:

Mean=2.53

median=2

mode=2

range=3

Step-by-step explanation:

1, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4, 4

MEAN

Add up all data values to get the sum

Count the number of values in your data set

Divide the sum by the count

38/15=2.53

MEDIAN

Arrange data values from lowest to the highest value

The median is the data value in the middle of the set

If there are 2 data values in the middle the median is the mean of those 2 values.

MODE

Mode is the value or values in the data set that occur most frequently.

RANGE

18-15=3

5 0
3 years ago
The photography club decided to go on a field trip to the Andy Warhol museum. They had to break into smaller groups once they go
Diano4ka-milaya [45]
A)
Let x represent the cost of 1 student, and y the cost of 1 teacher.

B)
In the first group, there's 25 students and 2 teachers. Their total cost is $97.50
So 25x + 2y = 97.50
In the second group, there's 32 students and 3 teachers. Their total cost is $127
So 32x + 3y = 127

We get the following system of equations:
25x + 2y = 97.50 (1)
32x + 3y = 127 (2)

C)
25x + 2y = 97.50 (1)
32x + 3y = 127 (2)

In equation (1)
25x + 2y = 97.50
25x + 2y - 2y = 97.50 - 2y
25x = 97.50 - 2y
25x / 25 = 97.50/25 - 2y/25
x = 3.9 - (2/25)y

In equation (2), let's replace x by its algebraic value
32x + 3y = 127
32(-2/25y + 3.9) + 3y = 127
11/25y + 124.8 = 127
11/25y + 124.8 - 124.8 = 127 - 124.8
11/25y = 2.2
(11/25y) / (11/25) = 2.2 / (11/25)
y = 5

x = -2/25y + 3.9
x = -2/25 * 5 + 3.9
x = 3.5

So the cost of each student is $3.5, and the cost of each teacher is $5.

Hope this helps! :)




4 0
3 years ago
Such that |x-a|&lt;\varepsilon and $x-b|&lt;\varepsilon. can $a$ be countable? can $a$ be uncountable?
Brrunno [24]
It will be uncountable

3 0
3 years ago
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