This is relationship is an inverse variation. In this relationship the product of x and y always equals a constant. In this case the product is 8. i.e. xy = 8.
Answer:
-4 4 4.5 8 20.5 32
Step-by-step explanation:
f
g(x) = f(g(x))
Given, f(x) = 2x²
and g(x) = x - 2
Now f(g(x)) = f(x - 2) = 2(x - 2)²
We know that (a - b)² = a² - b² + 2ab
Using this we expand f(g(x)). We get:
f(g(x)) = 2{x² - 4x + 4}
Similarly, g(f(x)) = g(2x²) = 2x² - 2
Now, f(g(-2)) = 2[(-2)² - 4(-2) + 4] = 2(16) = 32.
Also, g(f(-2)) = 2[(-2)² - 2] = 2(2) = 4.
f(g(3.5)) = 2{(3.5)² -4(3.5) + 4} = 2[12.25 - 14 + 4] = 2(2.25) = 4.5.
g(f(3.5)) = 2{(3.5)² -2} = 2{12.25 - 2} = 2(10.25) = 20.5.
f(g(0)) = 2{0 - 4(0) + 4} = 2(4) = 8.
g(f(0)) = 2{0 - 2} = 2(-2) = -4.
Arranging them in ascending order, we get:
-4 4 4.5 8 20.5 32 would be the sequence.
Answer:
See below
Step-by-step explanation:
1-0+0-2+1=0, so since 0/11=0, it's divisible by 11
The rule for divisibility by 11 is that you subtract then add then subtract then add and so on, and if you get a number divisible by 11 or equal to 0, then it's divisible by 11.
Hope that made sense.
answer:
N(t)=2×
17
15
step by step explain:
before lesson (t=0), she knows 2 words.
after a week (t=1), she knows
2×(1+70%)=3.4 words
after one more week (t=2), she knows
3.4×(1+70%)=5.78 words
one more week later (t=3), she knows
5.78×(1+70%)=9.826 words
and so on ...
from pattern shown above, we know that she knows
2×
words after t weeks
so N(t)=2×
after 4 weeks (t=4), she knows 2×
=16.7042≈17 words
for learning 5000 words, she need:
2×
=5000
=2500
t log(1.7)=log(2500)
t=
=14.7448727
≈15 (round up)
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