All categories

1 year ago

The perimeter of the triangle below is 73 units. Find the value of x.

Mathematics

2 answers:

Evgesh-ka [11]1 year ago

6 0

Answer:

3x+4x-1+x+2=73

8x+1=73

8x=73-1

8x=72

8x/8=72/8

x=9

In-s [12.5K]1 year ago

3 0

<h2><u>Solution</u>:</h2>

Perimeter (p) of a triangle:

$p = a + b + c$

P = 73 units

To find the value of x

$73 = 3x + 4x - 1 + x + 2$

→ $73 = 8x + 1 \\ 73 - 1 = 8x$

→ $8x = 72$

→ $\frac{8x}{8} = \frac{72}{8}$

$x = 9$

You might be interested in

Billy left home at 9 a.M. And rode his bicycle to the park at an average speed of 10 miles per hour here I got the park at 9:30

tamaranim1 [39]

Answer:

Park is <u>5 miles</u> from Billy's home.

Step-by-step explanation:

Given:

Billy left home at 9 a.m. And rode his bicycle to the park at an average speed of 10 miles per hour here and got the park at 9:30 a.m.

Now, to find the distance from park to Billy,s home.

Time it took Billy to rode his bicycle from park to home is from 9.30 a.m to 9.30 p.m.

So, the time = (9.30 - 9.00) = 30 minutes

$=\frac{30}{60}$ $=0.5\ hour.$

Speed = 10 miles per hour.

Now, to get the distance from park to Billy's home we put formula:

$Distance=Speed\times Time.$

$Distance=10\times 0.5$

$Distance=5\ miles.$

Therefore, park is 5 miles from Billy's home.

3 0

2 years ago

Calculate the following limit:

aleksklad [387]

$\lim_{x\to\infty}\dfrac{\sqrt x}{\sqrt{x+\sqrt{x+\sqrt x}}}=\\
\lim_{x\to\infty}\dfrac{\dfrac{\sqrt x}{\sqrt x}}{\dfrac{\sqrt{x+\sqrt{x+\sqrt x}}}{\sqrt x}}=\\
\lim_{x\to\infty}\dfrac{1}{\sqrt{\dfrac{x+\sqrt{x+\sqrt x}}{x}}}=\\
\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\dfrac{\sqrt{x+\sqrt x}}{x}}}=\\
\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\dfrac{\sqrt{x+\sqrt x}}{\sqrt{x^2}}}}=\\$
$\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\sqrt{\dfrac{x+\sqrt x}{x^2}}}}=\\\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\sqrt{\dfrac{1}{x}+\dfrac{\sqrt x}{\sqrt{x^4}}}}}=\\\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\sqrt{\dfrac{1}{x}+\sqrt{\dfrac{x}{x^4}}}}}=\\
\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\sqrt{\dfrac{1}{x}+\sqrt{\dfrac{1}{x^3}}}}}=\\
=\dfrac{1}{\sqrt{1+\sqrt{0+\sqrt{0}}}}=\\$
$=\dfrac{1}{\sqrt{1+0}}=\\
=\dfrac{1}{\sqrt{1}}=\\
=\dfrac{1}{1}=\\
1
$

8 0

3 years ago

What is 3 4/8 + 7 1/2

vivado [14]

Answer:

Step-by-step explanation:

3+7=10

4/8=1/2

12+1/2=1

10+1=11

6 0

3 years ago