Points of intersection are (0,0),(0,8),(10,0),(4,6) plugging them into the equation you get 0,24,10,22. I don't know if you're looking for max value or min value.
Answer:
x = √K - 2xh - h²/a
Step-by-step explanation:
a(x+h)²=k
a * x² + 2xh + h² = k
a * x² = K - 2xh - h²
x² = K - 2xh - h²/a
x = √K - 2xh - h²/a
Answer:
−32q−6
Step-by-step explanation:
10+4(−8q)+4⋅−410+4(-8q)+4⋅-4
Multiply −8-8 by 44.
10−32q+4⋅−410-32q+4⋅-4
Multiply 44 by −4-4.
10−32q−1610-32q-16
Subtract 1616 from 1010.
Answer:
D
Step-by-step explanation:
Solution:-
The standard sinusoidal waveform defined over the domain [ 0 , 2π ] is given as:
f ( x ) = sin ( w*x ± k ) ± b
Where,
w: The frequency of the cycle
k: The phase difference
b: The vertical shift of center line from origin
We are given that the function completes 2 cycles over the domain of [ 0 , 2π ]. The number of cycles of a sinusoidal wave is given by the frequency parameter ( w ).
We will plug in w = 2. No information is given regarding the phase difference ( k ) and the position of waveform from the origin. So we can set these parameters to zero. k = b = 0.
The resulting sinusoidal waveform can be expressed as:
f ( x ) = sin ( 2x ) ... Answer
