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3 years ago

74.94×103=

Mathematics

2 answers:

madreJ [45]3 years ago

7 0

Answer:

74940

Step-by-step explanation:

I believe you meant 74.94*10^3. The ^ indicates exponentiation. 10^3 is equivalent to 1000; Multiplying 74.94 by 1000; we get 74940.

STatiana [176]3 years ago

3 0

7494 thousand is the answer

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Solve for x. 21/2x−3/4(2x+5)=3/8

Savatey [412]

Simplify \frac{21}{2}x
2

21
x to \frac{21x}{2}
2

21x

\frac{21x}{2}-\frac{3}{4}(2x+5)=\frac{3}{8}
2

21x
−
4

3
(2x+5)=
8

3

2 Simplify \frac{3}{4}(2x+5)
4

3
(2x+5) to \frac{3(2x+5)}{4}
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3(2x+5)

\frac{21x}{2}-\frac{3(2x+5)}{4}=\frac{3}{8}
2

21x
−
4

3(2x+5)
=
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3 Multiply both sides by 44 (the LCM of 2, 42,4)
42x-3(2x+5)=\frac{3}{2}42x−3(2x+5)=
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3

4 Expand
42x-6x-15=\frac{3}{2}42x−6x−15=
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5 Simplify 42x-6x-1542x−6x−15 to 36x-1536x−15
36x-15=\frac{3}{2}36x−15=
2

3

6 Add 1515 to both sides
36x=\frac{3}{2}+1536x=
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3
+15

7 Simplify \frac{3}{2}+15
2

3
+15 to \frac{33}{2}
2

33

36x=\frac{33}{2}36x=
2

33

8 Divide both sides by 3636
x=\frac{\frac{33}{2}}{36}x=
36

2

33

9 Simplify \frac{\frac{33}{2}}{36}
36

2

33

to \frac{33}{2\times 36}
2×36

33

x=\frac{33}{2\times 36}x=
2×36

33

10 Simplify 2\times 362×36 to 7272
x=\frac{33}{72}x=
72

33

11 Simplify \frac{33}{72}
72

33
to \frac{11}{24}
24

11

x=\frac{11}{24}x=
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X=11 over 24

4 0

3 years ago

Read 2 more answers

Someone please help me I will be so thankful

Volgvan

1/2 = 0.5 = 50% was found.

Looking at the scale, there are 5 dashes from 0 to 10,000. This means that each dash is worth $2,000. The thermometer is marked 2.5 dashes up; 2.5(2000) = 5000.

5000/1000 = 1/2; 1/2 = 0.5; 0.5 = 50%.

8 0

3 years ago

Use Distributive Property to simplify<br><br> -7(3m - 4)<br><br> HEEEEEEEEEEEEEEEEELP!!!!!!

pishuonlain [190]

Answer:

-21m+28

Step-by-step explanation:

$-7(3m-4)\\\\-21m+28\\\\\left \{ {{-7*3m=-21m} \atop {-7*-4=28}} \right.$

Hope this helps.

3 0

3 years ago

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The temperature reading from a thermocouple placed in a constant-temperature medium is normally distributed with mean μ, the act

cluponka [151]

Answer: 0.3061.

Step-by-step explanation:

Given : The temperature reading from a thermocouple placed in a constant-temperature medium is normally distributed with mean $\mu$ , the actual temperature of the medium, and standard deviation $\sigma$ .

Let X be the random variable that represents the reading of the thermometer.

Confidence level : $=95\%$

We know that the z-value for 95% confidence interval is 1.96.

Then, we have

$-1.96$ $z=\dfrac{X-\mu}{\sigma}$

$\Rightarrow\ -1.96\sigma$

But all readings are within 0.6° of $\mu$ .

So, $1.96\sigma=0.6$

$\Rightarrow\ \sigma=\dfrac{0.6}{1.96}=0.30612244898\approx0.3061$

Hence, the required standard deviation will be

7 0

3 years ago

If f(x) is differentiable for the closed interval [-1, 4] such that f(-1) = -3 and f(4) = 12, then there exists a value c, -1&lt

Alex_Xolod [135]

Answer: Choice A, f ' (c) = 3

============================================

Work Shown:

f(-1) = -3 means the point (-1,-3) is on the f(x) curve.

f(4) = 12 means (4,12) is on the f(x) curve as well.

Compute the slope of the line through those two points.

Slope formula

m = (y2 - y1)/(x2 - x1)

m = (12 - (-3))/(4 - (-1))

m = (12+3)/(4+1)

m = 15/5

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Through the mean value theorem (MVT), there exists at least one value c such that f ' (c) = 3, where -1 < c < 4, and f(x) is a continuous and differentiable function on this interval in question.

Visually, there exists at least one tangent line that has the same slope of the secant line mentioned. Lines with equal slopes, and different y intercepts, are parallel.

5 0

4 years ago

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