Answer:
5.9125in^2
Step-by-step explanation:
Step one:
Given data
Dimension of square= 5.25 in
Area of sqaure= 5.25^2= 27.5625 in^2
We are told that the sides of the circle touch the sides of the square
hence the diameter of the circle is 5.25in
radius= 5.25/2= 2.625 in
Area of circle= πr^2
Area of circle = 3.142*2.625^2
Area of circle=3.142*6.890625
Area of circle= 21.65 in^2
Step two:
The area that is not inside the circle
=Area of square-Area of circle
=27.5625- 21.65
=5.9125in^2
Answer:
it must also have the root : - 6i
Step-by-step explanation:
If a polynomial is expressed with real coefficients (which must be the case if it is a function f(x) in the Real coordinate system), then if it has a complex root "a+bi", it must also have for root the conjugate of that complex root.
This is because in order to render a polynomial with Real coefficients, the binomial factor (x - (a+bi)) originated using the complex root would be able to eliminate the imaginary unit, only when multiplied by the binomial factor generated by its conjugate: (x - (a-bi)). This is shown below:
where the imaginary unit has disappeared, making the expression real.
So in our case, a+bi is -6i (real part a=0, and imaginary part b=-6)
Then, the conjugate of this root would be: +6i, giving us the other complex root that also may be present in the real polynomial we are dealing with.
Answer:
f(2) = 729
Step-by-step explanation:
f(x) = 3^(x + 4)
Let x =2
f(2) = 3^(2 + 4)
f(2) = 3^(6)
f(2) = 729
Answer:
He is approximately 166.6 m ahead of Ravi.
If it's right please mark BRAINLIEST
The answer is 7 because it goes 10th 100th and the thirty one is thousands