Answer:
4th choice 
Step-by-step explanation:
<u>Definition of the inverse of a function</u>
A function g is the inverse of a function f if whenever y=f(x) then x=g(y). In other words, applying f and then g is the same thing as doing nothing. We can write this in terms of the composition of f and g as g(f(x))=x. The domain of f becomes the range of g and the range of f becomes the domain of g
To solve for the inverse of the function 
Let 


Switch sides

Take square roots on both sides

Add 4 on both sides to solve for y

We have two solutions

To determine which one of these to be chosen not that in the given choices we can eliminate the first two since x cannot be negative
The third choice can also be eliminated since
is a decreasing function for
So the last answer choice is correct and the inverse of
is given by 
Answer:4th choice 
Note
Domain of (x-4)² is [4, ∞) since x ≥ 4 and (x-4)² cannot be negative
Range of (x-4)² is [0, ∞)
Domain of
is [0, ∞)
Range of
is [4, ∞)
so indeed the domain of (x-4)² has become the range of
and the range of (x-4)² has become the domain of 
For number 3, write something along the lines in your own words like The risks involved in the use of condoms in combating the spread of HIV and AIDS is the condom can break, the condom can be slipped off without knowledge, and the condom does not protect from oral sex.
Answer:
2^4 or 16
Step-by-step explanation:
We know that a^b / a^c = a^(b-c)
2^9 / 2^5
2^(9-5)
2^4 or 16
1. What’s the probablity of a second person winning the small prize?
There are now 99 total marbles, and 24 silver marbles. So, 24/99 is 0.24 probability.
2. Which player is most likely to win a big prize?
Since each player draws a silver marble (aka a small prize) there are less small prize marbles in the bag after each turn. So, the first person would have a 5% chance (or 0.05)of winning the big prize gold marble, but the last person would have a slightly bigger chance (5.15% or 0.0515) of winning a big prize.
3. How could the game be made fair for each player?
Well it’s quite simple, just have each player return their marble and the number of marbles would be kept constant, giving everyone an equal chance. Or you could have them all play at the same time, either way.
4. Same answer as 3