A cookie jar contains 2 chocolate chip cookies, 5 oatmeal raisin cookies, and 3 sugar cookies.

2 answers:

7 0

The answer willl be a) 1/15, because in the question, it tells you that the event B happens without replacement. A will be 2/10 because theres two chocolate chip cookies out of all 10 items in the jar and probability of b) will be 3/9 as you have to take one away guven that there is no replacement. You then times the two probabilities together: 2/10 x 3/9 which gives you 6/90. This is then simplified into 1/15 by dividingboth parts of the fraction by a common factor :3. The answer will be A

Elden [556K]4 years ago

3 0

$|\Omega|=10\cdot9=90\\
|A\cap B|=2\cdo3=6\\\\
P(A \cap B)=\dfrac{6}{90}=\dfrac{1}{15}\Rightarrow \text{A}$

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Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

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In this problem, we have that:

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