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3 years ago

What is the average of -2.6, 1.8, -3.3, -2.7, 2.2 ? I dont understand this.

1 answer:

4 0

Average = Mean

To find the mean, add up the numbers and divide it by how many numbers there are.

So, $-2.6+1.8+(-3.3)+(-2.7)+2.2=-4.6$

There are 5 numbers in total.

$-4.6 \div 5=-0.92$

To do these types of division, ignore the decimal and add a 0 at the end.

So we can do:
$-460\div5=-92$

And put back the decimal.
Hope this helps :)

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David is making rice for his guests based on a recipe that requires rice, water, and a special blend of spice, where the rice-to

steposvetlana [31]

Answer:

8 servings

Step-by-step explanation:

At the ratio of 15:1, the 75 grams of rice in one serving will require 75/15 = 5 g of spice. David's inventory of 40 g of spice is enough for ...

40 g/(5 g/serving) = 8 servings

7 0

3 years ago

Read 2 more answers

Do these two in the figure appear to be similar?

iVinArrow [24]

Hello,

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4 years ago

If you are reading this please help!!!!

Soloha48 [4]

Given:

$1. -3 x^{2}\left(4 x^{3}-7\right)\\$2. $(6 x-5)(2 x+3)$\\3. $(3 x-1)\left(x^{2}+5 x-2\right)$$

To find:

The product of the polynomials.

Solution:

1. $-3 x^{2}\left(4 x^{3}-7\right)$ $=-3 x^{2}(4 x^{3}) -3 x^{2}(-7)$

Multiply the numerical coefficient and add the powers of x.

$=-12 x^{5}+21 x^{2}$

2. $(6 x-5)(2 x+3)=6 x(2 x+3)-5(2x+3)$

Multiply each term of first polynomial with each term of 2nd polynomial.

Multiply the numerical coefficient and add the powers of x.

$=12 x^2+18x-10 x-15$

$=12 x^2+8x-15$

3. $(3 x-1)\left(x^{2}+5 x-2\right)=3 x(x^{2}+5 x-2)-1(x^{2}+5 x-2)$

Multiply each term of first polynomial with each term of 2nd polynomial.

Multiply the numerical coefficient and add the powers of x.

$=3x^{3}+15 x^2-6x-x^{2}-5 x+2$

Add or subtract like terms together.

$=3x^{3}+14 x^2-11x+2$

The answer for multiplying polynomials:

$1. -12 x^{5}+21 x^{2}$

$2. \ 12 x^2+8x-15$

$3. \ 3x^{3}+14 x^2-11x+2$

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3 years ago

WILL GIVE BRAINIEST TO THE PERSON THAT ANSWERS ALL THREE QUESTIONS ASAP!

Radda [10]

Answer:

1. Your answer would be C) 2√3-5√2.

2. Your answer would be -39.7i.

3. Your answer would be -1.

Step-by-step explanation:

8 0

3 years ago

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An envelope contains three cards: a black card that is black on both sides, a white card that is white on both sides, and a mixe

Over [174]

Answer:

There is a 2/3 probability that the other side is also black.

Step-by-step explanation:

Here let B1: Event of picking a card that has a black side

B2: Event of picking a card that has BOTH black side.

Now, by the CONDITIONAL PROBABILITY:

$P(B_2/B_1 ) = \frac{P(B_1\cap B_2)}{P(B_1)}$

Now, as EXACTLY ONE CARD has both sides BLACK in three cards.

⇒ P (B1 ∩ B2) = 1 /3

Also, Out if total 6 sides of cards, 3 are BLACK from one side.

⇒ P (B1 ) = 3 /6 = 1/2

Putting these values in the formula, we get:

$P(B_2/B_1 ) = \frac{P(B_1\cap B_2)}{P(B_1)} = \frac{1}{3} \times\frac{2}{1} = \frac{2}{3}$

⇒ P (B2 / B1) = 2/3

Hence, there is a 2/3 probability that the other side is also black.

5 0

3 years ago