Step-by-step explanation:
the area of the circle is
x=1,241
A triangle is cut out of a square whose length is 12 feet. What will be the approximate area, in square feet, of the remaining b
1 answer:
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Answer:
x = 2.5
Step-by-step explanation:
<em>For the equation:</em>
<em />
<em>The cross product is:</em>
4 × x = 2 × 5
<em>Solving for X</em>
<em /><em />
<em />
<em>And reducing:</em>
x = 2.5
Consider the picture.
Let MN be the midsegment of the trapezoid.
That is M is the midpoint of AD, N is the midpoint of BC.
Being the midsegment of the trapezoid, MN is parallel to the bases.
Let O and K be the intersections of the diagonals with the midsegment.
MN//AB, so MO//AB, and since M is the midpoint of DA, O must be the midpoint of DB,
Similarly we prove that K is the midpoint of CA.
Thus O is F and K is E.
O and K lie on the midsegment MN, so F and E lie on the midsegment.
MO is a midsegment of triangle ABD so |MO|=1/2 |AB|=1/2 * 10=5
MK is a midsegment of triangle ADC, so |MK|=1/2 * |DC|=1/2 * 22=11
|OK|=|MK|-|MO|=11-5=6 (units)
Let MN be the midsegment of the trapezoid.
That is M is the midpoint of AD, N is the midpoint of BC.
Being the midsegment of the trapezoid, MN is parallel to the bases.
Let O and K be the intersections of the diagonals with the midsegment.
MN//AB, so MO//AB, and since M is the midpoint of DA, O must be the midpoint of DB,
Similarly we prove that K is the midpoint of CA.
Thus O is F and K is E.
O and K lie on the midsegment MN, so F and E lie on the midsegment.
MO is a midsegment of triangle ABD so |MO|=1/2 |AB|=1/2 * 10=5
MK is a midsegment of triangle ADC, so |MK|=1/2 * |DC|=1/2 * 22=11
|OK|=|MK|-|MO|=11-5=6 (units)
Answer:
≈ -2.76
≈ -2.8 (rounded to nearest tenths place)
Step-by-step explanation:
For this case we have that by definition, the surface area of a cone is given by:
Where:
r: It is the cone radius
s: It's the slant height
According to the data we have:
Substituting:
Thus, the surface area of the cone is
Answer:
Option B