Answer:
5 units
Step-by-step explanation:
Let point O be the point of intersection of the kite diagonals.
|OF| = 2, |OH| = 5
|FH| = |OF| + |OH| = 2 + 5 = 7
FH and EG are the diagonals of the kite. Hence the area of thee kite is:
Area of kite EFGH = (FH * EG) / 2
Substituting:
35 = (7 * |EG|) / 2
|EG| * 7 = 70
|EG| = 10 units
The longer diagonal of a kite bisects the shorter one, therefore |GO| = |EO| = 10 / 2 = 5 units
x = |GO| = |EO| = 5 units
Answer:
(1,3)
Step-by-step explanation:
Answer:
Do you mean:
(1+(2/3))j = 15
((3/3)+(2/3))j = 15
((3+2)/3)j = 15
(5/3)j = 15
j = 15 / (5/3)
j = 15 * (3/5)
j = 9
Step-by-step explanation:
the answer is five point six five, 5.65
Answer:
w=120°
x=45°
y=30°
Step-by-step explanation:
AT=PR, AR=PT
Therefore, y=30°
y+45°=x+30°
x=45°
In triangle:
y+30°+w=180°
w=120°
Hope it helps! :)