The local high school is hosting an ice cream social for new students. They

Mathematics

1 answer:

loris [4]2 years ago

7 0

Answer: 13/23 - APEX

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Find the area of the figure, in square meters, to 1 decimal place.

yawa3891 [41]

To find area, you multiply the two dimensions, or base x height.

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hope it helps

sorry if it didn't, you didn't provide much clarification

8 0

2 years ago

Read 2 more answers

PLEASE NO LINKS OR I WILL REPORT YOUR ACCOUNT

Artemon [7]

<h3>Answer: 200.96 ft^2 (choice C)</h3>

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Work Shown:

A = pi*r^2

A = 3.14*8^2

A = 200.96

Note that the radius r = 8 is half of the diameter d = 16. I'm using the approximation pi = 3.14, which means the area is approximate. To get a more accurate answer, use more decimal digits of pi. The units of the area are in square feet, which can be written as "sq ft" or as "ft^2".

5 0

2 years ago

Hi need help for this maths question

Sauron [17]

a) If f(y) is a probability density function, then both f(y) ≥ 0 for all y in its support, and the integral of f(y) over its entire support should be 1. eˣ > 0 for all real x, so the first condition is met. We have

$\displaystyle \int_{-\infty}^\infty f(y) \, dy = \frac14 \int_0^\infty e^{-\frac y4} \, dy = -\left(\lim_{y\to\infty}e^{-\frac y4} - e^0\right) = \boxed{1}$

so both conditions are met and f(y) is indeed a PDF.

b) The probability P(Y > 4) is given by the integral,

$\displaystyle \int_{-\infty}^4 f(y) \, dy = \frac14 \int_0^4 e^{-\frac y4} \, dy = -\left(e^{-1} - e^0\right) = \frac{e - 1}{e} \approx \boxed{0.632}$

c) The mean is given by the integral,

$\displaystyle \int_{-\infty}^\infty y f(y) \, dy = \frac14 \int_0^\infty y e^{-\frac y4} \, dy$

Integrate by parts, with

$u = y \implies du = dy$

$dv = e^{-\frac y4} \, dy \implies v = -4 e^{-\frac y4}$

Then

$\displaystyle \int_{-\infty}^\infty y f(y) \, dy = \frac14 \left(\left(\lim_{y\to\infty}\left(-4y e^{-\frac y4}\right) - \left(-4\cdot0\cdot e^0\right)\right) + 4 \int_0^\infty e^{-\frac y4} \, dy\right)$