we know that
A half-acre is equal to----------> 
Let
x---------> the length side of the building lot
y--------> the width side of the building lot
A------> Area of the building lot
x=5y-------> equation 1


--------> equation 2
substitute equation 1 in equation 2
![2,023.43=[5y]*y](https://tex.z-dn.net/?f=2%2C023.43%3D%5B5y%5D%2Ay)

<u>Find the value of x</u>

therefore
<u>the answer is</u>
the dimensions of the building lot are 100.55 m* 20.11 m
Answer:
(x2 , y2) = (22,50)
Step-by-step explanation:
Given:
m1 : m2 = 1:4
(x1 , y1) = (7 , 5)
(X ,Y) = (10 ,14)
Find:
(x2 , y2)
Computation:
X = (m1x2 + m2x1) / (m1+m2)
10 = [(1)(x2) + (4)(7)]/(1+4)
10 = [x2 + 28]/5
22 = x2
Y = (m1y2 + m2y1) / (m1+m2)
14 = [(1)(y2) + (4)(5)]/(1+4)
14 = [y2 + 20]/5
70 = y2 + 20
50 = y2
(x2 , y2) = (22,50)
I think it would be D hope it helps!!!
Answer:
-20
Step-by-step explanation: