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3 years ago

1 plus 1 is equal to 2 but jonas has 19 more

Mathematics

1 answer:

Vlada [557]3 years ago

4 0

Answer:

Jonas has 21.

Step-by-step explanation:

19+2= 21

Since he has 19 more than what the other person has, which is 2.

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There are two different maps of ohio. The scale on the first map is 1 cm to 10 km. The distance from cleveland to clncinnati is

aev [14]

Answer: Distance from Cleveland to Cincinnati on the second map is 8 km.

Step-by-step explanation:

Since we have given that

The scale on the first map is

$1\ cm:10\ km$

That means

$1\ cm=10\ km$

Distance from Cleveland to Clncinnati = 40 cm

So,

$1\ cm=10\ km\\\\40\ cm=10\times 40\ km\\\\40\ cm=400\ km$

Similarly, Scale on the second map is given by

$1\ cm:50\ km\\\\i.e.\\\\1\ cm=50\ km$

So, our 400 km in second map will be

$\frac{400}{50}\ km=8\ km$

Hence, Distance from Cleveland to Cincinnati on the second map is 8 km.

5 0

3 years ago

5/32 × 64y/100 please help :,)

ladessa [460]

Answer:

1/10y

Step-by-step explanation

(5/32(64))(y)/100

3 0

3 years ago

Suppose X, Y, and Z are random variables with the joint density function f(x, y, z) = Ce−(0.5x + 0.2y + 0.1z) if x ≥ 0, y ≥ 0, z

kompoz [17]

$f_{X,Y,Z}(x,y,z)=\begin{cases}Ce^{-(0.5x+0.2y+0.1z)}&\text{for }x\ge0,y\ge0,z\ge0\\0&\text{otherwise}\end{cases}$

is a proper joint density function if, over its support, $f$ is non-negative and the integral of $f$ is 1. The first condition is easily met as long as $C\ge0$ . To meet the second condition, we require

$\displaystyle\int_0^\infty\int_0^\infty\int_0^\infty f_{X,Y,Z}(x,y,z)\,\mathrm dx\,\mathrm dy\,\mathrm dz=100C=1\implies \boxed{C=0.01}$

b. Find the marginal joint density of $X$ and $Y$ by integrating the joint density with respect to $z$ :

$f_{X,Y}(x,y)=\displaystyle\int_0^\infty f_{X,Y,Z}(x,y,z)\,\mathrm dz=0.01e^{-(0.5x+0.2y)}\int_0^\infty e^{-0.1z}\,\mathrm dz$

$\implies f_{X,Y}(x,y)=\begin{cases}0.1e^{-(0.5x+0.2y)}&\text{for }x\ge0,y\ge0\\0&\text{otherwise}\end{cases}$

Then

$\displaystyle P(X\le1.375,Y\le1.5)=\int_0^{1.5}\int_0^{1.375}f_{X,Y}(x,y)\,\mathrm dx\,\mathrm dy$

$\approx\boxed{0.12886}$

c. This probability can be found by simply integrating the joint density:

$\displaystyle P(X\le1.375,Y\le1.5,Z\le1)=\int_0^1\int_0^{1.5}\int_0^{1.375}f_{X,Y,Z}(x,y,z)\,\mathrm dx\,\mathrm dy\,\mathrm dz$

$\approx\boxed{0.012262}$

7 0

3 years ago

Factorise the following: A. 4xy-16 B. xy+2xy-x C. 2x²-18x+12 D. 5xy+20x-9y-36

Burka [1]

=4(xy−4)

3xy−x

=x(3y−1)

2x²−18x+12

=2(x²−9x+6)

5xy+20x−9y−36

=(y+4)(5x−9)

6 0

2 years ago

You receive an inheritance of $15,500, and you place the full amount into a bank account. The bank pays a simple interest rate o

g100num [7]

To solve this we need to figure out what 7.5% of 15,500 is. (It’s 1162.5). Now we know that after one year it is a total of 16,662.5. We then figure out what 7.5% of 16,662.5 is, which is 1,249.6875. You then add that to 16,662.5 which comes out to 17,912.1875. We then figure out 7.5% of that is 1,343.4140625. We then add that to the last total which is 19,255.6015625 and we simplify that to 19,256 and we find out that the final total is $19,256. But it wants how much have we earned which means we need to subtract the original from the new, which is 3756 and we add a unit.

Meaning the final answer is $3,756.

6 0

3 years ago