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SVETLANKA909090 [29]
3 years ago
11

How to find sides of gon with meaure of each angle exterior?

Mathematics
1 answer:
MrMuchimi3 years ago
8 0
All exterior angles of n-gon always add up to 360°

To find the number of sides:

\text {Number of sides = }  \dfrac{360}{\text {size of one exterior angle}}
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Find 6 times as many as,2plus 9
Alex17521 [72]

Answer:

The answer is 21.

Step-by-step explanation:

6 * 2 = 12 + 9 = 21

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3 years ago
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Describe a transformation or series of transformations that demonstrates the congruence between figures A and B.
N76 [4]

Answer:

90 clockwise (or counterclockwise) rotation and then a reflection over the axis between the two shape (those two steps go in any order)

Step-by-step explanation:

for this lets mark the innermost point of each shape a (blue or A) and a' (red or B)* and the second point b and b'

here we see that the two shapes are in a position to where they seem reflected over a non-existent third diagonal axis, though this is not the case, we need to bring the shape into a position where it can be transformed to the quadrant of shape B and overlap the shape

so when you have a reflection over a diagonal axis, we can rotate or reflect the shape to a new quadrant, and perform the step thats not the first, so say we made a reflection over the X-axis, the shape is now in the lower half of the graph with shape B, from here we perform our last step wich is to rotate the shape into the quadrant of shape B in a clockwise motion, now a and a' overlap and b and b' overlap, same for c, c',d and d'

(*the ' in this case is called a prime symbol, when used, distinguishes two points or lines on a graph, A' = A prime)

5 0
2 years ago
Giselle has $16.25 in her wallet and needs to get to her uncle���s house 8 miles away. a taxi costs $2.50 for the first mile and
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3 years ago
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Feliz [49]

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Find the exact value of cos theta​, given that sin thetaequalsStartFraction 15 Over 17 EndFraction and theta is in quadrant II.
vova2212 [387]

Answer:

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Step-by-step explanation:

For this case we know that:

sin \theta = \frac{15}{17}

And we want to find the value for cos \theta, so then we can use the following basic identity:

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cos \theta =\pm \sqrt{1-sin^2 \theta}

And if we replace the value given we got:

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For our case we know that the angle is on the II quadrant, and on this quadrant we know that the sine is positive but the cosine is negative so then the correct answer for this case would be:

cos \theta = -\frac{8}{17}

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