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RideAnS [48]
3 years ago
11

Jane is 20 lbs heavier than Alive. If Jane's weight is 120% that of Alice, find the weight of Alice

Mathematics
1 answer:
mojhsa [17]3 years ago
3 0

Answer:

Alice's weight is 100 lbs.

Step-by-step explanation:

Let's denote Jane's weight by J, and Alice's weight by A.

The exercise says that Jane is 20 lbs heavier than Alice. So that if you add 20 lbs to Alice's weight, you get Jane's weight. In equation form:

20+A=J

It also mentions that Jane's weight is 120% that of Alice. So that if you multiply Alice's weight by 1.2, you get Jane's weight. In equation form:

1.2 \cdot A=J

Plugging this second equation onto the first equation, we get:

20+A=1.2A

And now solving for A:

20=1.2A-A

20=0.2A

\frac{20}{0.2}=A

100=A

Therefore Alice's weight is 100 lbs.

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Solve -2/3x > 8 or -2/3x < 4.
vekshin1
<h3>Answer: Choice C</h3>

{x | x < -12 or x > -6}

=========================================================

Explanation:

Let's solve the first inequality for x.

(-2/3)x > 8

-2x > 8*3

-2x > 24

x < 24/(-2)

x < -12

The inequality sign flips when we divide both sides by a negative value.

Let's do the same for the second inequality.

(-2/3)x < 4

-2x < 4*3

-2x < 12

x > 12/(-2)

x > -6

The conclusion of each section is that x < -12 or x > -6 which points us to <u>choice C</u> as the final answer.

Side note: The intervals x < -12 and x > -6 do not overlap in any way. There's a gap between the two pieces. We consider these intervals to be disjoint. The number line graph is below.

8 0
2 years ago
Someone please help!!
OLga [1]

Answer:

f(-8) = 64

Step-by-step explanation:

Since x =-8, we need to use x^2 since -8 <0

(-8)^2 = 64

When x = -8 f(-8) = 64

3 0
3 years ago
Read 2 more answers
What is the simplified form of the product x^2+8x+15/x-4•x^2-16/2x+6
Evgesh-ka [11]

Final result :

 (x + 5) • (x + 4)

 ———————

         2        

Step by step solution :

Step  1  :

           x2 - 16

Simplify   ———————

           2x + 6

Step  2  :

Pulling out like terms :

2.1     Pull out like factors :

  2x + 6  =   2 • (x + 3)

Trying to factor as a Difference of Squares :

2.2      Factoring:  x2 - 16

Theory : A difference of two perfect squares,  A2 - B2  can be factored into  (A+B) • (A-B)

Proof :  (A+B) • (A-B) =

        A2 - AB + BA - B2 =

        A2 - AB + AB - B2 =

        A2 - B2

Note :  AB = BA is the commutative property of multiplication.

Note :  - AB + AB equals zero and is therefore eliminated from the expression.

Check : 16 is the square of 4

Check :  x2  is the square of  x1

Factorization is :       (x + 4)  •  (x - 4)

Polynomial Long Division :

2.3    Polynomial Long Division

Dividing :  x + 4

                             ("Dividend")

By         :    x + 3    ("Divisor")

dividend     x  +  4

- divisor  * x0     x  +  3

remainder         1

Quotient :  1  

Remainder :  1  

Equation at the end of step  2  :

 (((x2)+8x)+15) (x+4)•(x-4)

 ——————————————•———————————

     (x-4)        2•(x+3)  

Step  3  :

           x2 + 8x + 15

Simplify   ————————————

              x - 4    

Trying to factor by splitting the middle term

3.1     Factoring  x2 + 8x + 15

The first term is,  x2  its coefficient is  1 .

The middle term is,  +8x  its coefficient is  8 .

The last term, "the constant", is  +15

Step-1 : Multiply the coefficient of the first term by the constant   1 • 15 = 15

Step-2 : Find two factors of  15  whose sum equals the coefficient of the middle term, which is   8 .

     -15    +    -1    =    -16

     -5    +    -3    =    -8

     -3    +    -5    =    -8

     -1    +    -15    =    -16

     1    +    15    =    16

     3    +    5    =    8    That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  3  and  5

                    x2 + 3x + 5x + 15

Step-4 : Add up the first 2 terms, pulling out like factors :

                   x • (x+3)

             Add up the last 2 terms, pulling out common factors :

                   5 • (x+3)

Step-5 : Add up the four terms of step 4 :

                   (x+5)  •  (x+3)

            Which is the desired factorization

Equation at the end of step  3  :

 (x + 5) • (x + 3)   (x + 4) • (x - 4)

 ————————————————— • —————————————————

       x - 4            2 • (x + 3)  

Step  4  :

Canceling Out :

4.1    Cancel out  (x+3)  which appears on both sides of the fraction line.

Canceling Out :

4.2    Cancel out  (x-4)  which appears on both sides of the fraction line.

Final result :

 (x + 5) • (x + 4)

 ——————---

         2        

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Finger [1]

Answer:

I believe it's A

Step-by-step explanation:

Hope this helps!

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barxatty [35]
Check the attached file for the solution.

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