the problem would be set up as 6+(7*x)=41
first u take off the number 6 by subtracting it from itself to cancel it out then u do the same to the number 41
7x =41 now u need to cancel out the number 7 attatched to the x so u divikde it by itself and then do the same to the other side so 41 divided by 7 =5.9
so x =5.9
Can you rephrase it? (maybe write it out in numbers?)
Answer:
sqrt(104) =x
Step-by-step explanation:
We can use the Pythagorean theorem since this is the right triangle.
a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse.
2^2 + 10^2 = x^2
4+100 = x^2
104 = x^2
Take the square root of each side
sqrt(104) = sqrt(x^2)
sqrt(104) =x
