3 years ago

Subtract 8/m - 11/3m. A: 8m-11/3m B: 24m-11/3m C: -3/3m D: 3/3m

Mathematics

1 answer:

grandymaker [24]3 years ago

8 0

Alright, so if we multiply (8/m) by (3/3), we get 24/3m to get the same denominator as 11/3m

(24-11)/3m = 13/3m

You might be interested in

The function f (t) = 12(1 +0.03) can be used to determine the population, in thousands of a town t years

Alja [10]

f= the original amount of people, a steady growth throughout the years

t=time

In 1955 the population was 12 thousand. Compared to the current population of 12.36 thousand, the population then was roughly 77%.

5 0

3 years ago

Caroline, Colin & Sarah share some money.

julia-pushkina [17]

Answer:

2/9

Step-by-step explanation:

After Caroline's share,

1 - 1/9 = 8/9 is left

Sarah gets:

1/(1+3) of 8/9

1/4 × 8/9

2/9

4 0

3 years ago

<img src="https://tex.z-dn.net/?f=x%3D-2%5C%5Cx%2B3y%3D4" id="TexFormula1" title="x=-2\\x+3y=4" alt="x=-2\\x+3y=4" align="absmid

Natali5045456 [20]

X + 3y -4 =0 or x=4 I think that’s the answer

4 0

3 years ago

What are all the true statements

Finger [1]

Answer:

i am going to say number 1 even though they all sound right hope i helped <3

Step-by-step explanation:

3 0

4 years ago

An FM radio station broadcasts at 84 megahertz (MHz). What is the energy of each photon in Joule? Use h = 6.6 * 10 ^ (- 34) * j

iragen [17]

Answer:

$E=5.544*10^{-26} J$

Step-by-step explanation:

The equation for photon energy is given by:

$E=hf$

Where:

$h=Planck\hspace{3}constant=6.6*10^{-34} \\f=Frequency\hspace{3}of\hspace{3}the\hspace{3}wave=84000000Hz$

This equation telling us that the higher the frequency of the photon, the greater its energy. And the longer the photon wavelength, the lower its energy.

So, replacing the data provided in the previous equation:

$E=(6.6*10^{-34} )*(84000000)=5.544*10^{-26} J$

7 0

3 years ago