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Radda [10]
4 years ago
5

The area of the ice surface of a skating rink is about 221 yd2. The rink is about the shape of a rectangle where the ice-surface

width is 4 yd longer than its length. Find the dimensions of the surface. A. length = 13 yd, width = 17 yd B. length = 21 yd, width = 17 yd C. length = 17 yd, width = 21 yd D. length = 17 yd, width = 13 yd

Mathematics
1 answer:
ella [17]4 years ago
6 0
Check the picture below

notice, the length cannot be a negative value.. so is not -17

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Answer:

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Step-by-step explanation:

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3 years ago
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Answer:

75°

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we can form a triangle to help us understand how to solve this problem:

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8 0
3 years ago
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prohojiy [21]

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torisob [31]
The answer would be $6.49.
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3 years ago
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