The area of the ice surface of a skating rink is about 221 yd2. The rink is about the shape of a rectangle where the ice-surface
width is 4 yd longer than its length. Find the dimensions of the surface. A. length = 13 yd, width = 17 yd B. length = 21 yd, width = 17 yd C. length = 17 yd, width = 21 yd D. length = 17 yd, width = 13 yd
1 answer:
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Circumference of a circle = 
They are all multiplied by each other
r = radius
we know our radius is 40
and...
= 3.14
so we would use this expression
3.14 x 40 x 2
As a added bonus ill solve it for you :P
3.14 x 40 x 2 = 251.2
The circumference of this ice skating rink is 251.2 feet
They are all multiplied by each other
r = radius
we know our radius is 40
and...
so we would use this expression
3.14 x 40 x 2
As a added bonus ill solve it for you :P
3.14 x 40 x 2 = 251.2
The circumference of this ice skating rink is 251.2 feet
Answer:
very easy
Step-by-step explanation:
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