The area of the ice surface of a skating rink is about 221 yd2. The rink is about the shape of a rectangle where the ice-surface
width is 4 yd longer than its length. Find the dimensions of the surface. A. length = 13 yd, width = 17 yd B. length = 21 yd, width = 17 yd C. length = 17 yd, width = 21 yd D. length = 17 yd, width = 13 yd
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Firstly , we need to draw diagram
we are given
opposite =300
adjacent =750
now, we can use tan formula
now, we can find x
we get
so,
angle of depression is 21.8 degree.....Answer
