Answer:
Step-by-step explanation:
Dy/dx = -y inx iny
(y in x in y) dx + dy = 0
(y in x in y ) dx = - dy
(in x )dx = - (1/ y in y) dy
you just need to integrate both sides
Hope this helps
Q11
Suppose the two numbers are x and y so xy = 3000
the HCF = 10
we know that product of two numbers = product of their HCF and LCM
XY = HCF * LCM
3000 = 10 * LCM
3000/10 = LCM
300 = LCM
Answer 300
Q12 : Let us say second number is x so
product of x and 160 = product of HCF and LCM of ( x and 160 )
160 x = 32 * 1760
x= 32 * 1760 / 160
x= 352
Answer : 352
Answer:
n
Step-by-step explanation:
maybe not for sure