The area of the ice surface of a skating rink is about 221 yd2. The rink is about the shape of a rectangle where the ice-surface
width is 4 yd longer than its length. Find the dimensions of the surface. A. length = 13 yd, width = 17 yd B. length = 21 yd, width = 17 yd C. length = 17 yd, width = 21 yd D. length = 17 yd, width = 13 yd
1 answer:
You might be interested in
Check the picture below.
so the lateral area will be just the area of the sides, namely excluding the bases at top and bottom, thus
