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Allisa [31]
3 years ago
12

I’ll give points + brainalist (:

Mathematics
2 answers:
andrey2020 [161]3 years ago
5 0

Answer:

B x \leq 1

Step-by-step explanation:

Isolate the x.

-5x + 10 \geq 5\\-5x \geq -5\\x \leq 1

The \geq sign flipped to \leq , because you're dividing with a negative number.

rjkz [21]3 years ago
3 0

Answer:

The right answer to the question is b

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Find the sum of the geometric series 512+256+ . . .+4
mario62 [17]

\bf 512~~,~~\stackrel{512\cdot \frac{1}{2}}{256}~~,~~...4

so, as you can see above, the common ratio r = 1/2, now, what term is +4 anyway?

\bf n^{th}\textit{ term of a geometric sequence}\\\\a_n=a_1\cdot r^{n-1}\qquad \begin{cases}n=n^{th}\ term\\a_1=\textit{first term's value}\\r=\textit{common ratio}\\----------\\r=\frac{1}{2}\\a_1=512\\a_n=+4\end{cases}

\bf 4=512\left( \cfrac{1}{2} \right)^{n-1}\implies \cfrac{4}{512}=\left( \cfrac{1}{2} \right)^{n-1}\\\\\\\cfrac{1}{128}=\left( \cfrac{1}{2} \right)^{n-1}\implies \cfrac{1}{2^7}=\left( \cfrac{1}{2} \right)^{n-1}\implies 2^{-7}=\left( 2^{-1}\right)^{n-1}\\\\\\(2^{-1})^7=(2^{-1})^{n-1}\implies 7=n-1\implies \boxed{8=n}

so is the 8th term, then, let's find the Sum of the first 8 terms.

\bf \qquad \qquad \textit{sum of a finite geometric sequence}\\\\S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad \begin{cases}n=n^{th}\ term\\a_1=\textit{first term's value}\\r=\textit{common ratio}\\----------\\r=\frac{1}{2}\\a_1=512\\n=8\end{cases}

\bf S_8=512\left[ \cfrac{1-\left( \frac{1}{2} \right)^8}{1-\frac{1}{2}} \right]\implies S_8=512\left(\cfrac{1-\frac{1}{256}}{\frac{1}{2}}  \right)\implies S_8=512\left(\cfrac{\frac{255}{256}}{\frac{1}{2}}  \right)\\\\\\S_8=512\cdot \cfrac{255}{128}\implies S_8=1020

7 0
4 years ago
Describe how you know whether an equation will be true for all values of x or true for no values of x
love history [14]

Answer:

<h2>brainiest me</h2>

Step-by-step explanation:

The value returned is TRUE if all of the values in x are TRUE (including if there are no values), and FALSE if at least one of the values in x is FALSE. Otherwise the value is NA (which can only occur if na.rm = FALSE and ... contains no FALSE values and at least one NA value).

5 0
3 years ago
How do you divide 85 and 5?
AVprozaik [17]
Division is like sharing so 85 things that are shared between 5 people
85÷5=17 that is how much each person gets
so 17 is your answer
5 0
3 years ago
Read 2 more answers
4a^2-9(x+y)^2 factories this step by step pls. Anyone !! Help me pls!!​
xxTIMURxx [149]
  • Answer:

<em>(2a - 3x - 3y)(2a + 3x + 3y)</em>

  • Step-by-step explanation:

<em>Hi there !</em>

use formula

<em>a</em><em>² - </em><em>b</em><em>² = (a - b)(a + b)</em>

<em>a</em><em> = 2a</em>

<em>b</em><em> = 3(x + y)</em>

<em />

<em>4a² - 9(x+y)² =</em>

<em>= [2a - 3(x + y)][2a + 3(x + y)]</em>

<em>= (2a - 3x - 3y)(2a + 3x + 3y)</em>

<em />

<em>Good luck !</em>

5 0
3 years ago
Please help me with the question
mars1129 [50]

(i) The mean is

\displaystyle E(X) = \sum_x x \, P(X = x) \\\\ E(X) = 1\cdot0.175 + 2\cdot0.315 + 3\cdot0.211 + 4\cdot0.092 + 5\cdot0.207 \\\\ \boxed{E(X) = 2.839}

The variance is

V(X) = E((X - E(X))^2) = E(X^2) - E(X)^2

Compute the second moment E(X^2) :

\displaystyle E(X^2) = \sum_x x^2 \, P(X = x) \\\\ E(X) = 1^2\cdot0.175 + 2^2\cdot0.315 + 3^2\times0.211 + 4^2\times0.092 + 5^2\times0.207 \\\\ E(X^2) = 9.997

Then the variance is

\boxed{V(X) \approx 1.9171}

(ii) For a random variable Z=aX+b, where a,b are constants, we have

E(Z) = E(aX+b) = E(aX) + E(b) = a E(X) + b

and

V(Z) = E((aX+b)^2) - E(aX+b)^2 \\\\ V(Z) = E(a^2 X^2 + 2ab X + b^2) - (a E(X) + b)^2 \\\\ V(Z) = a^2 (E(X^2) - E(X)^2) \\\\ V(Z) = a^2 V(X)

Then for Y=\frac{X+3}2, we have

E(Y) = \dfrac12 E(X) + \dfrac32 \\\\ \boxed{E(Y) = 2.918}

E(Y^2) = E\left(\left(\dfrac{X+3}2\right)^2\right) = \dfrac14 E(X^2) + \dfrac32 E(X) + \dfrac94 \\\\ \boxed{E(Y^2) \approx 9.0028}

3 0
2 years ago
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