Answer:
Normal daughters and Hemophiliac son
Explanation:
Females exhibit hemophilia and colorblindness in homozygous genotype only.
The genotype of hemophiliac woman= X^hX^h
The genotype of colorblind man= X^cY
A cross between X^hX^h and X^cY would produce progeny in the following phenotype ratio= 1 Normal but carrier daughters:1 Hemophiliac son
Cellular respiration is also a catabolic process because it breaks the small molecules from digestion into even smaller ones as ATP is created. These are both very important processes, because ATP is what your cells use to produce body heat, move your muscles, and other essential bodily functions.
The child would possibly still be considered as tall because the tall genes is Dominant, and the only way that recessive allele is selected is when the child receives two recessive allele
There's a great picture that I attached below that is a great representation