Question

Solve for y (4y+4)/3 + (7y-8)/6 = 15

Answer 1

$\dfrac{4y+4}{3}+\dfrac{7y-8}{6}=15\ \ \ \ \ |multiply\ both\ sides\ by\ 6\\\\6\cdot\dfrac{4y+4}{3}+6\cdot\dfrac{7y-8}{6}=6\cdot15\\\\2(4y+4)+1(7y-8)=90\\\\8y+8+7y-8=90\\\\15y=90\ \ \ \ |divide\ both\ sides\ by\ 15\\\\\boxed{y=6}$