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4 years ago

Solve for y (4y+4)/3 + (7y-8)/6 = 15

1 answer:

5 0

$\dfrac{4y+4}{3}+\dfrac{7y-8}{6}=15\ \ \ \ \ |multiply\ both\ sides\ by\ 6\\\\6\cdot\dfrac{4y+4}{3}+6\cdot\dfrac{7y-8}{6}=6\cdot15\\\\2(4y+4)+1(7y-8)=90\\\\8y+8+7y-8=90\\\\15y=90\ \ \ \ |divide\ both\ sides\ by\ 15\\\\\boxed{y=6}$

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For what values of x is f(x) = square root of x-4 equal to 4?

zaharov [31]

Answer:

x = 20

Step-by-step explanation:

given f(x) = $\sqrt{x-4}$ , we have to solve

$\sqrt{x-4}$ = 4

Square both sides

( $\sqrt{x-4}$ )² = 4²

x - 4 = 16 ( add 4 to both sides )

x = 20

As a check

$\sqrt{20-4}$ = $\sqrt{16}$ = 4 ← correct

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borishaifa [10]

Answer:

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Step-by-step explanation:

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3 years ago

The table displays the frequency of scores for a calculus class on an exam. The mean of the exam scores is 3.5. Score 1 2 3 4 5

vladimir1956 [14]

Answer:

f=11

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Explanation:

We are given that

a.Mean of the exam score, $\bar x$ =3.5

Score(x) frequency C.F

1 1 1

2 3 4

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$\sum f_ix_i=1(1)+2(3)+3(f)+4(13)+5(4)=1+6+3f+52+20=79+3f$

$(\bar x)=\frac{\sum f_ix_i}{\sum f_i}$

Using the formula

$3.5=\frac{79+3f}{21+f}$

$73.5+3.5f=79+3f$

$3.5f-3f=79-73.5$

$0.5f=5.5$

$f=\frac{5.5}{0.5}=11$

b.Mode:The number which is repeat most times .

4 repeat most times

Hence, mode of all exam scores=4

N=32

N is even

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Median= $\frac{16th+17th}{2}=\frac{4+4}{2}=\frac{8}{2}=4$

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