Ask question

Ask question

All categories

4 years ago

9

Find the area pls hurry I need for homework pls show work or will not accept and I will give Brainly

1 answer:

Marizza181 [45]4 years ago

8 0

Answer:

132 ft2

Step-by-step explanation:

The area of the rectangle is A=LxW

A= 9 x 11

Area of the rectangle is 99 ft2

To find the height of the triangle, subtract the width of the rectangle from the total height.

15-9= 6

The area of the triangle is A= 1/2 bh

A= 1/2 (11)(6)

Area of the triangle is 33 ft2

The total area is 99 + 33, which is 132 ft2

You might be interested in

Which of the following equations is equivalent to S=pi r^2 h

lara31 [8.8K]

The equation that is equivalent to S=pi r^2 h is h = S/pir^2

<h3>Subject of formula</h3>

This is a way of representing a variable with another. Given the equation

S=pi r^2 h

We are to make 'h" the subject of the formula.

Divide both sides by pir^2

S/pir^2 =pi r^2 h/pir^2

h = S/pir^2

Hence the equation that is equivalent to S=pi r^2 h is h = S/pir^2

Learn more on subject of formula here: brainly.com/question/657646

#SPJ1

4 0

2 years ago

The histogram below shows information about the number of books students read in a month:

max2010maxim [7]

Answer:

Option C is true - The number of students who read 4 books or fewer

Step-by-step explanation:

Here, to find the mean and median, we do not have proper information or specific values. We just have the ranges, so both the mean and median cannot be determined. So, options A and B are not correct.

We can see two bins covering the 9 or more books, so option D cannot be true either.

Therefore, only option C is left and that is true.- the number of students who read 4 books or fewer.

6 0

3 years ago

HELPPPP WHATS THE LATERAL AREA

AVprozaik [17]

Answer:

3cm

Step-by-step explanation:

6 0

3 years ago

The picture this is math 1 for apex learning

noname [10]

Answer:

C.

Step-by-step explanation:

(f+g)(x) ➡ f(x) + g(x)

x/2 - 2 + 2x^2 + x - 3 = 2x^2 + 3x/2 -5

3 0

3 years ago

Learning Task 3

ASHA 777 [7]

Answer:

1. The sides are: 38.5, 39.5, 40.5 and 41.5

2. Presently, Inzo is 15 years old and Miz is 10 years old

3. $Distance = 3682km$

4. Possible pairs are: (12, 14), (16, 18) and (20, 24)

5. $L < 38m$

Step-by-step explanation:

The question has lots of missing details. See the comment section for complete question

Solving (a):

Given

Shape: Quadrilateral

Sides: Consecutive

$Perimeter = 160$

Let one of the sides be x. The other sides will be x + 1, x + 2 and x + 3.

So, the perimeter is:

$Perimeter = x + x + 1 + x + 2 + x + 3$

This gives:

$160 = x + x + 1 + x + 2 + x + 3$

Collect Like Terms

$160 -1-2-3= x+x+x+x$

$154= 4x$

Divide both sides by 4

$38.5 = x$

$x =38.5$

<em>So, the sides are: 38.5, 39.5, 40.5 and 41.5</em>

<em></em>

Solving (b):

Given

Presently: $Inzo = 10 + Miz$

Five years ago: $Miz - 5= \frac{1}{3} * (Inzo-5)$ --- (Missing from the question)

Required: Determine their present ages

Substitute $10 + Miz$ for Inzo in the second equation

$Miz - 5 = \frac{1}{3} * (10 + Miz - 5)$

$Miz - 5 = \frac{1}{3} * (Miz + 5)$

Multiply both sides by 3

$3Miz - 15 = Miz + 5$

Collect Like Terms

$3Miz -Miz = 15 + 5$

$2Miz= 20$

Divide both sides by 2

$Miz = 10$

Substitute 10 for Miz in $Inzo = 10 + Miz$

$Inzo = 10 + 5$

$Inzo = 15$

<em>So presently, Inzo is 15 years old and Miz is 10 years old</em>

Solving (3):

Given

Express Train:

$Speed = 100kph$

$Time = t$

Local Train:

$Speed = 45kph$

$Time = t + 45$

Required: Determine the distance between A and B

Distance is calculated as:

$Distance = Speed * Time$

For the express train:

$Distance = 100 * t$

For the local train

$Distance = 45 * (45 + t)$

Distance between both stations are equal; So,

$100 * t = 45 * (45 + t)$

$100 t = 2025 + 45t$

Collect Like Terms

$100 t -45t= 2025$

$55t= 2025$

Divide by 55

$t = 36.82$

Substitute 36.82 for t in $Distance = 100 * t$

$Distance = 100 * 36.82$

$Distance = 3682km$

Solving (4):

Let the even numbers be: n and n + 2.

Sum greater than 24: $n + n + 2 > 24$

Sum less than 60: $n + n + 2 < 60$

So, we have:

$n + n + 2 > 24$

$2n + 2 > 24$

Collect Like Terms

$2n > 24-2$

$2n > 22$

$n > 11$

$n + n + 2 < 60$

$2n + 2< 60$

Collect Like Terms

$2n < 60-2$

$2n < 58$

Divide by 2

$n$

So, we have:

$n > 11$ and $n < 29$

So, possible pairs are: (12, 14), (16, 18) and (20, 24)

Solving (5):

Given

$Perimeter < 152m$

Required: Find the possible lengths

Let the length be L.

Perimeter is calculated as:

$Perimeter =4 * L$

$Perimeter =4 L$

So, we have:

$4L < 152m$

Divide through by 4

$L < 38m$

Hence, length is less than 38m (e.g. 37m)

5 0

3 years ago