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egoroff_w [7]
3 years ago
6

The Mars Cereal Company has two different cereal boxes for Mars Cereal. The large box is 8 inches wide, 11 inches high, and 3 in

ches deep. The small box is 6 inches wide, 10 inches high, and 2.5 inches deep.
a. How much more cardboard is needed to make the large box than the small box?
b. How much more cereal does the large box hold than the small box?
Mathematics
2 answers:
lubasha [3.4K]3 years ago
6 0

Answer:

a)90  square inches

b)104 cubic inches

Step-by-step explanation:

Dimensions of the bigger box

W= 8 in

H=11 in

D= 3 in

Dimensions of the smaller box

w= 6 in

h= 10 in

h= 2.5 in

therefore, difference in the area of the cupboard

=2[ WH+HD+WD] - 2[wh+hd+wd]

= 2[8*11+11*3+8*3]- 2[6*10+10*2.5+6*2.5]

=290- 200= 90 square inches

volume of the large cupboard = WHD= 8*11*3= 264 cubic in

volume of the small cupboard= whd= 6*10*2.5= 150 cubic in

therefore,  264-150= 114 cubic in more cereal does the large box hold than the small box

Alisiya [41]3 years ago
4 0

Answer:

I am kind of confused what is the final awsner

Step-by-step explanation:

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Damm [24]

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3 years ago
Simplify -3x^3(2x^2+3)+9x^4
SIZIF [17.4K]

Answer:

ANSWER = −6x^5 +9x^4 − 9x^3

Step-by-step explanation:

Let's simplify step-by-step.

(−3x^3) (2x^2 + 3) + 9x^4

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3 0
3 years ago
In circle E, AC=4, CG=6, and AH=3, Find HB and EG. If necessary, round to the tenths place.
bezimeni [28]
Using theorem about secant segments we can write,
AB*AH=AG*AC
AC=4,
CG=6
AG=AC+CG=4+6=10
AH=3
AB= AH+HB=AH+x=3+x
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9+3x=40
3x=40-9
3x=31
x=31/3≈10.3
HB≈10.3
EG=HB/2 (as radius and diameter)
EG=10.3/2≈5.2




3 0
3 years ago
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