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Maslowich
3 years ago
8

Someone please help me with this algebra

Mathematics
1 answer:
labwork [276]3 years ago
3 0
QUADRATIC \: \: \: RESOLUTIONS \\ \\ \\ \\Function \: to \: model \: the \: height \: of \: the \\ Grasshopper \: above \: the \: ground \: is \: \\ given \: by \: \: - \\ \\ h(t) \: \: = \: \: - {t}^{2} \: + \: \frac{4}{3} t \: + \: \frac{1}{4} \\ \\ \\ When \: the \: grasshopper \: will \: be \: at \: \\ the \: ground \: , \: \: \\ \\ h(t) \: = \: 0 \\ \\ - {t}^{2} \: + \: \frac{4}{3} t \: + \: \frac{1}{4} \: = \: 0 \\ \\ - 12{t}^{2} \: + \: 16 t \: + 3 \: = \: 0 \\ \\ \: \: \: 12 {t}^{2} \: - \: 16t \: - \: 3 \: = \: 0 \\ \\ \: \: \: 12 {t}^{2} \: + \: 2t \: - \: 18t \: - 3 \: = \: 0 \\ \\ \: \: 2t \: (6t + 1) \: - 3 \: (6t + 1) \: = \: 0 \\ \\ \: (2t - 3) \: (6t + 1) \: \: = \: \: 0 \\ \\ Neglecting \: the \: negative \: value \: \\ as \: time \: cannot \: be \: negative \: \: ,\\ \\ We \: get \: \: - \: \\ \\ t \: \: = \: \: \frac{3}{2} \\ \\ \\ Hence \: \: , \: \: After \: \: || \: \: 1.5 \: seconds \: \: || \: , \: the \: \\ Grasshopper \:  will \: land \: on \: the \: ground \: .
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The revenue function for a sporting goods company is given by R(x)=x⋅p(x) dollars where x is the number of units sold and p(x)=4
Zina [86]

The maximum revenue generated is $160000.

Given that, the revenue function for a sporting goods company is given by R(x) = x⋅p(x) dollars where x is the number of units sold and p(x) = 400−0.25x is the unit price. And we have to find the maximum revenue. Let's proceed to solve this question.

R(x) = x⋅p(x)

And,  p(x) = 400−0.25x

Put the value of p(x) in R(x), we get

R(x) = x(400−0.25x)

R(x) = 400x - 0.25x²

This is the equation for a parabola.  The maximum can be found at the vertex of the parabola using the formula:

x = -b/2a from the parabolic equation ax²+bx+c   where a = -0.25,  b = 400 for this case.

Now, calculating the value of x, we get

x = -(400)/2×-0.25

x = 400/0.5

x = 4000/5

x = 800

The value of x comes out to be 800. Now, we will be calculating the revenue at x = 800 and it will be the maximum one.

R(800) = 400x - 0.25x²

= 400×800 - 0.25(800)²

= 320000 - 160000

= 160000

Therefore, the maximum revenue generated is $160000.

Hence, $160000 is the required answer.

Learn more in depth about revenue function problems at brainly.com/question/25623677

#SPJ1

5 0
2 years ago
If in the equation [ 4/t-1 = 2/w-1 ] t ≠ 1 and w ≠ 1, then t =
schepotkina [342]

t=2w-1

OPTION A is the correct answer...

3 0
3 years ago
Given f(x)=x^2-4x+5, what's the value when f(2)
Reil [10]

If you were to replace the x's with 2, your equation would turn into:

(2)^2-4(2)+5

From there, you'd just solve.

4-8+5=1

Your answer would be 1.

7 0
3 years ago
Maria is saving money so she can go to a professional football game. Maria has $25. She saves $5 a week.
slava [35]
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7 0
3 years ago
Read 2 more answers
Evaluate n+2x2 when n=3 and x=−2.
krok68 [10]

Answer:

When n=3 and x=−2  the answer is 11.

Step-by-step explanation:

Given:

Let p (n,x) be the function such that

p (n,x) = n + 2x^{2}

To Find:

p (n,x) = p ( 3, -2) = ?

Solution:

p (n,x) = n + 2x^{2}

Substituting n = 3 and x = -2 we get

p (3, -2) = 3 + 2(-2)^{2}

Negative square gives positive number therefore (-2)²=4

p (3, -2) = 3 + 2\times 4

p (3, -2) = 3 + 8\\p (3, -2) = 11

When n=3 and x=−2  the answer is 11.

7 0
3 years ago
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