Answer:
The rearrangement can be 45, 987 , 310
Step-by-step explanation:
Here, we want to rearrange the number such that 9 is worth 10 times as what it is worth presently
The value of 9 presently is 90,000
So 10 times as worth will be 10 * 90,000 = 900,000
So we can have the new arrangement as;
45, 987, 310
The answer to your question is 134:)
Answer:
24 ft
Step-by-step explanation:
a^2 + b^2 = c^2
7^2 + b^2 = 25^2
7^2 - 25^2 = -b^2
49 - 625 = -b^2
-576 = -b^2
24 = b
Our number system is in base 10, which means that each digit has a value that is a multiple of 10.
For ex:
877 literally means
8 7 7 where each digit is multiplied by
10^ 2 10 ^1 10^0 respectively
which is 8 * 10^ 2 + 7 * 10^1 + 7 * 10^0 = 8 * 100 + 7 * 10 + 7 * 1 = 800 + 70 + 7 = 877
Binary is in base 2, so each of its digits (which can only be 0 or 1) are multiplied by multiples of 2 (2^0, 2^1, 2^2 ect.)
To find what 877 is in binary you can do the following:
the symbol : means divide and i'll write the quotient + the remainder
877 : 2 = 438 + 1 (438 is the quotient, 1 is the remainder)
438 : 2 = 219 + 0
219 : 2 = 109 + 1
109 : 2 = 54 + 1
54 : 2 = 27 + 0
27 : 2 = 13 + 1
13 : 2 = 6 + 1
6 : 2 = 3 + 0
3 : 2 = 1 + 1
1: 2 = 0 + 1
now write ALL off the remainders from BOTTOM to TOP:
1101101101
use a similar step for octal (use 8 instead of 2 as the divisor) and hexidecimal (use 16 instead of 2 as the divisor)
