This information will be modeled using the formula
thus we shall have:
Sn=ar^n
where:
a=first term
r=common ratio
from the information:
a=30 ft
r=60/100=3/5=0.6
therefore the formula will be
Sn=30(0.6)^n
where n is the number of terms:
thus when n=5 th sum will be:
S5=30(0.6)^5
S5=30(0.6)^5
S5=2.33 ft
Answer: 2.33 ft
Answer:
Step-by-step explanation:
Answer:
Step-by-step explanation:
i want to help you but what do you need help with??
Answer:
Step-by-step explanation:
This is already factored for us, which is really nice, so now all we need to do is apply the Zero Product Property to the sets of parenthesis and solve for x, which will give us the 2 times that the object is on the ground.
x + 1 = 0 so
x = -1
x - 9 = 0 so
x = 9
We all know that time cannot ever be negative, so the time that the object is on the ground is 9 seconds after it's launched (which was from an initial height of 45 meters).
Answer:
Raymond's mistake was on the last step, since he didn't square root both sides
The correct answer should be
Step-by-step explanation:
Good luck!
