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3 years ago

Sleep problems are fairly common among both adults and children. TF

2 answers:

7 0

<span>It is false that sleep problems are fairly common among both adults and children. Sleep problems are developmental in nature, that means, it could be grown out over time. Usually it happens from toddlerhood to adolescence. If it continues from teenage years to adulthood, then you need to consult a doctor or psychologist.</span>

brilliants [131]3 years ago

5 0

Answer:

true

Explanation: i took the test got it right

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When it comes to saving money, what is a good rule of thumb

Mamont248 [21]

Buy what u need when u need it not what u want when u want my dad always said

7 0

3 years ago

Read 2 more answers

Early personal computer users remember the cumbersome, user-unfriendly "DOS" system. When Apple introduced System 1 and Microsof

Aleksandr [31]

Early personal computer users remember the cumbersome, user-unfriendly "DOS" system. When Apple introduced System 1 and Microsoft introduced Windows, both of which were much easier to use, these new products diffused rapidly because of their relative advantage .

Option A

<u>Explanation: </u>

A product's dominance and market appeal over similar items. A competitive advantage is usually accomplished by giving better value to customers through either reducing prices or delivering added quality and service that justify higher costs.

That idea is based on consumer brand and product perceptions and does not necessarily reflect the actual characteristics of this product or service. The definition helps companies to consider that customers would choose to use this product or whether a rival would rather remain faithful to the already existing product.

8 0

3 years ago

if the interest rate on a savings account is 0.018%, approximately how much money do you need to keep in this account for 1 year

scZoUnD [109]

A = $9.99, the amount needed after 1 year
r = 0.018% = 0.00018, interest rate
n = 12, compoundings per year
t = 1, one year duration

Let P = required balance at the beginning of the year.
Then
$P(1+ \frac{r}{n} )^{nt} = A$
P(1 + 0.00018/12)¹² = 9.99
1.00018P = 9.99
P = $9.988 ≈ $9.99

Answer: $9.99

7 0

3 years ago

Each machine must be run by one of 19 cross-trained workers who are each available 35 hours per week. The plant has 10 type 1 ma

Mrac [35]

Answer:

The Linear programming model is given as below

Profit Function: $P=90X+120Y+150Z$

Constraints:

$2X+2Y+Z\leq 400$

$3X+4Y+6Z\leq 240$

$4X+6Y+5Z\leq 320$

$\dfrac{2X+2Y+Z}{40}\leq 10$

$\dfrac{3X+4Y+6Z}{40}\leq 6$

$\dfrac{4X+6Y+5Z}{40}\leq 8$

$\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19$

Explanation:

As the question is not complete, the complete question is found online and is attached herewith.

Let the number of product 1 to be produced is X, that of product 2 is Y and product 3 is Z

so the maximizing function is the profit function which is given as

$P=90X+120Y+150Z$

Now as the number of hours in a week are 40 and there are a total of 10 type 1 machines so the total number of machine 1 hours are 40*10=400 hours

As from the given table product 1 uses 2 machine hours of machine 1, product 2 uses 2 machine hours of machine 1 and product 3 uses 1 hour of machine 1 so

$2X+2Y+Z\leq 400$

Now as the number of hours in a week are 40 and there are a total of 6 type 2 machines so the total number of machine 2 hours are 40*6=240 hours

As from the given table product 1 uses 3 machine hours of machine 2, product 2 uses 4 machine hours of machine 2 and product 3 uses 6 hour of machine 2 so

$3X+4Y+6Z\leq 240$

Now as the number of hours in a week are 40 and there are a total of 8 type 3 machines so the total number of machine 3 hours are 40*8=320 hours

As from the given table product 1 uses 4 machine hours of machine 3, product 2 uses 6 machine hours of machine 3 and product 3 uses 5 hour of machine 3 so

$4X+6Y+5Z\leq 320$

Now as the machine 1 is used as 2X+2Y+Z in a week and the week is of 40 hours so the number of machines to be used are given as

$\dfrac{2X+2Y+Z}{40}\leq 10$

Now as the machine 2 is used as 3X+4Y+6Z in a week and the week is of 40 hours so the number of machines to be used are given as

$\dfrac{3X+4Y+6Z}{40}\leq 6$

Now as the machine 3 is used as 4X+6Y+5Z in a week and the week is of 40 hours so the number of machines to be used are given as

$\dfrac{4X+6Y+5Z}{40}\leq 8$

Now the workers are available for 35 hours so the worker available at the machine 1 is given as

$\dfrac{2X+2Y+Z}{35}$

That of machine 2 is given as

$\dfrac{3X+4Y+6Z}{35}$

That of machine 3 is given as

$\dfrac{4X+6Y+5Z}{35}$

As the total number of workers is 19 so the constraint is given as

$\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19$

So the Linear programming model is given as below

Profit Function: $P=90X+120Y+150Z$

Constraints:

$2X+2Y+Z\leq 400$

$3X+4Y+6Z\leq 240$

$4X+6Y+5Z\leq 320$

$\dfrac{2X+2Y+Z}{40}\leq 10$

$\dfrac{3X+4Y+6Z}{40}\leq 6$

$\dfrac{4X+6Y+5Z}{40}\leq 8$

$\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19$

4 0

3 years ago

Claremore Company received $7,000 as payment from Tulsa Company for a sale made on account in the previous month. Which of the f

Inessa [10]

Answer:

a. Cash 7,000 Accounts Receivable 7,000

Explanation:

As for the information provided, the payment is received for a sales made in last month, and thus entry at the time of sales shall be:

Accounts Receivables A/c Dr. $7,000

To Sales $7,000

Therefore, when the amount is collected today it will increase cash by debiting cash for the same amount.

Further, balance of accounts receivables will be decreased by crediting such account.

Therefore, correct option is

a. Cash 7,000 Accounts Receivable 7,000

7 0

3 years ago