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True [87]
3 years ago
12

Which expression is equal to the expression below?

Mathematics
1 answer:
gavmur [86]3 years ago
5 0

Hey there!

  1. \bold{(2\times6)^4}
  2. \bold{2\times6=12}
  3. \bold{12\times12\times12\times12}
  4. \bold{12\times12=144}
  5. \bold{144\times144=20,736}

         \bold{A.\downarrow}

  • \bold{4\times(2\times6)}
  • \bold{2\times6=12}
  • \bold{4\times12=48}
  • \bold{48\neq20,736}
  • \boxed{\bold{incorrect}}

      \bold{B.\downarrow}

  • \bold{8^4}
  • \bold{8\times8\times8\times8}
  • \bold{8\times8=64}
  • \bold{64\times64=4,096}
  • \bold{4,096\neq20,736}
  • \boxed{\bold{incorrect}}

 

         \bold{C.\downarrow}

  • \bold{2\times(6)^4}
  • \bold{6^4=1,296}
  • \bold{2\times1,296=2,592}
  • \bold{2,592\neq20,736}
  • \boxed{\bold{incorrect}}

          \bold{D\downarrow}

  • \bold{2^4\times6^4}
  • \bold{2^4=16}
  • \bold{6^4=1,296}
  • \bold{16\times1,296=20,736}
  • \bold{20,736=20,736}
  • \boxed{\boxed{\bold{correct}}}

\boxed{\boxed{\bold{Answer:D.2^4\times6^4}\checkmark}}

Good luck on your assignment and enjoy your day!

~\bold{LoveYourselfFirst:)}

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Step-by-step explanation:

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According to the information given in the exercise, the weight of one block is 1 kilogram. Knowing that the fort must have 40 blocks, the total weight is:

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 Since each snowflake weighs 3* 10^{-3} grams, need to divide the total weight calculated above by the weight of a snowfake.

Therefore, through this procedure you get the following result:

x=\frac{40\ grams}{3 * 10 ^{-3}\ grams}\\\\x\approx13,333

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A random sample of 10 parking meters in a beach community showed the following incomes for a day. Assume the incomes are normall
Vlad1618 [11]

Answer: (2.54,6.86)

Step-by-step explanation:

Given : A random sample of 10 parking meters in a beach community showed the following incomes for a day.

We assume the incomes are normally distributed.

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Standard deviation : \sigma=\sqrt{\dfrac{\sum^{10}_{i=1}{(x_i-\mu)^2}}{n}}

=\sqrt{\dfrac{(1.1)^2+(0.2)^2+(1.9)^2+(1.6)^2+(2.1)^2+(0.5)^2+(2.05)^2+(0.45)^2+(3.3)^2+(1.7)^2}{10}}

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The confidence interval for the population mean (for sample size <30) is given by :-

\mu\ \pm t_{n-1, \alpha/2}\times\dfrac{\sigma}{\sqrt{n}}

Given significance level : \alpha=1-0.95=0.05

Critical value : t_{n-1,\alpha/2}=t_{9,0.025}=2.262

We assume that the population is normally distributed.

Now, the 95% confidence interval for the true mean will be :-

4.7\ \pm\ 2.262\times\dfrac{3.0265}{\sqrt{10}} \\\\\approx4.7\pm2.16=(4.7-2.16\ ,\ 4.7+2.16)=(2.54,\ 6.86)

Hence, 95% confidence interval for the true mean= (2.54,6.86)

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Answer:

Step-by-step explanation:

If m = 4, z = 9 and r = 1/6

1. 3 + m = 3 + 4 = 7

2. z - m = 9 - 4 = 5

3. 12r = 12 × 1/6 = 2

4. 60r - 4 = 60(1/6) - 4 = 10-4 = 6

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