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3 years ago

Find the product (3a4+4)2

Mathematics

2 answers:

geniusboy [140]3 years ago

5 0

Answer:

The product is 9a^8+24a^4+16

Step-by-step explanation:

Since we have given that (3a^4+4)^2

As we know that (a+b)^2=a^2+2ab+b^2

So, it becomes, (3a^4 + 4)^2=(3a^4)^2+2\times 3a^4\times 4+(4)^2\\\\=9a^8+24a^4+16

Hence, the product is 9a^8+24a^4+16

asambeis [7]3 years ago

4 0

The result is

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The reason is the following:

The problem is an example of a notable product: "the sum multiplied by the diference is equal to the difference of squares", that is to say:

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By applying this to our question, we obtain that:

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An n-sided polygon has two of its exterior angles measuring 30° and 42°.The remaining exterior angles all measure 16° each. Find

finlep [7]

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

a. Apply Law of Cosines to find QR:

p² = q² + r² - 2qr × Cos P

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Plug in the values

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Blababa [14]

Answer:

$|A| = - 28$

Step-by-step explanation:

Given

$A = \left[\begin{array}{cc}-2&6\\3&5\end{array}\right]$

Required

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$A = \left[\begin{array}{cc}a&b\\c&d\end{array}\right]$

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3 years ago

Find the product (3a4+4)2​

Find the product (3a4+4)2