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klio [65]
4 years ago
6

Find the product (3a4+4)2​

Mathematics
2 answers:
geniusboy [140]4 years ago
5 0

Answer:

The product is 9a^<u>8</u>+24a^4+16

Step-by-step explanation:

Since we have given that (<em>3a^4+4)^2</em>

As we know that (a+b)^2=a^2+2ab+b^2

So, it becomes, (3a^4 + 4)^2=(3a^4)^2+2\times 3a^4\times 4+(4)^2\\\\=9a^8+24a^4+16

Hence, the product is <em>9a^8+24a^4+16</em>

asambeis [7]4 years ago
4 0

The result is

9

a

2

−

16

The reason is the following:

The problem is an example of a notable product: "the sum multiplied by the diference is equal to the difference of squares", that is to say:

(

a

+

b

)

⋅

(

a

−

b

)

=

a

2

−

b

2

.

By applying this to our question, we obtain that:

(

3

a

−

4

)

⋅

(

3

a

+

4

)

=

(

3

a

)

2

−

(

4

)

2

=

9

a

2

−

16

.

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Answer:

Step-by-step explanation:

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Step-by-step explanation:

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Which of the following is a solution of x^2 + 2x + 4?
Kaylis [27]

Answer:

\displaystyle x_1=-1+\sqrt{3}i

\displaystyle x_2=-1-\sqrt{3}i

Step-by-step explanation:

<u>Second-Degree Equation</u>

The second-degree equation or quadratic equation has the general form

ax^2+bx+c=0

where a is non-zero.

There are many methods to solve the equation, one of the most-used is by using the solver formula:

\displaystyle x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

The equation of the question has the values: a=1, b=2, c=4, thus the values of x are

\displaystyle x=\frac{-2\pm \sqrt{2^2-4\cdot 1\cdot 4}}{2\cdot 1}

\displaystyle x=\frac{-2\pm \sqrt{-12}}{2}

Since the square root has a negative argument, both solutions for x are imaginary or complex. Simplifying the radical

\displaystyle x=\frac{-2\pm 2\sqrt{-3}}{2}=-1\pm\sqrt{3}i

The solutions are

\displaystyle x_1=-1+\sqrt{3}i

\displaystyle x_2=-1-\sqrt{3}i

7 0
3 years ago
There are 14 boys and 6 girls in Emily’s class. One student in Emily’s class is chosen each day to hand out calculators to all t
kramer

Same girl can be chosen for both jobs, is the probability with replacement. Multiply the individual probabilities.

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A certain organization recommends the use of passwords with the following​ format: vowel commavowel, consonant comma consonant c
zimovet [89]

The password format is = inpray93

vowel , consonant, consonant, consonant, vowel, consonant, number, number.

There are 21 consonants, 5 vowels and 10 number choices (0-9)

Since, there are 21 consonants and repetition is allowed so for 2nd, 3rd, 4th, and 6th positions 21 choices are available. For 1st and 5th positions, 5 choices  are available and for 7th and 8th position there are 10 choices (0 to 9).

Passwords are not case sensitive which means upper case and lower case letters are same.

So, the number of passwords can be =

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Part (b) question is not given. But it can be opposite to the first part i.e when the password letters are case sensitive.

This means all the letters are different.

So, number of passwords will be =

10\times42\times42\times42\times10\times42\times10\times10

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4 0
3 years ago
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