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3 years ago

Find the product (3a4+4)2

Mathematics

2 answers:

geniusboy [140]3 years ago

5 0

Answer:

The product is 9a^8+24a^4+16

Step-by-step explanation:

Since we have given that (3a^4+4)^2

As we know that (a+b)^2=a^2+2ab+b^2

So, it becomes, (3a^4 + 4)^2=(3a^4)^2+2\times 3a^4\times 4+(4)^2\\\\=9a^8+24a^4+16

Hence, the product is 9a^8+24a^4+16

asambeis [7]3 years ago

4 0

The result is

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The reason is the following:

The problem is an example of a notable product: "the sum multiplied by the diference is equal to the difference of squares", that is to say:

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By applying this to our question, we obtain that:

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(

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Detmermine the best method to solve the following equation, then solve the equation. (3x-5)^2=-125

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For the given equation;

$(3x-5)^2=-125$

We shall begin by expanding the parenthesis on the left side, after which we would combine all terms on and move all of them to the left side, which shall yield a quadratic equation. Then we shall solve.

Let us begin by expanding the parenthesis;

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ANSWER:

$x=\frac{5+5i\sqrt[]{5}}{3},x=\frac{5-5i\sqrt[]{5}}{3}$

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Find the product (3a4+4)2​

Find the product (3a4+4)2