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Bas_tet [7]
3 years ago
13

Nat sews a triangle on an apron. The three sides of the triangle measure 3 inches, 4 inches, and 5 inches. Which best represents

the triangle That sews on her apron
Mathematics
1 answer:
maria [59]3 years ago
4 0

Answer:

Is a scalene right triangle

Step-by-step explanation:

Classify the triangle

By the interior angles

Applying the Pythagoras Theorem

c^{2}=a^{2} +b^{2}

substitute the values

5^{2}=3^{2} +4^{2}

25=25 ------> is true

therefore

Is a right triangle

By the length sides

The triangle has three unequal sides

therefore

Is a scalene triangle

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TIMED QUESTION NEED HELP FASTWhat values of b satisfy 3(2b + 3)2 = 36?
egoroff_w [7]

Answer:

\frac{-3+ 2\sqrt{3}}{2}\textrm{ and }\frac{-3- 2\sqrt{3}}{2}

Step-by-step explanation:

3(2b+3)^{2}=36\\\frac{3(2b+3)^{2}}{3}=\frac{36}{3}\\(2b+3)^{2}=12

Taking square root both sides, we get

\sqrt{(2b+3)^{2}}=\pm \sqrt{12}\\2b+3=\pm \sqrt{4\times 3}\\2b+3=\pm 2\sqrt{3}\\2b+3-3=\pm 2\sqrt{3}-3\\2b=-3\pm 2\sqrt{3}\\b=\frac{-3\pm 2\sqrt{3}}{2}\\b=\frac{-3+ 2\sqrt{3}}{2}\textrm{ or }b=\frac{-3- 2\sqrt{3}}{2}

Therefore, the values of b are:

\frac{-3+ 2\sqrt{3}}{2}\textrm{ and }\frac{-3- 2\sqrt{3}}{2}

5 0
4 years ago
Read 2 more answers
A survey is made to determine the number of households having electric appliances in a certain city. It is found that 75% have r
Mashcka [7]

Answer:

The probability that a household has at least one of these appliances is 0.95

Step-by-step explanation:

Percentage of households having radios P(R) = 75% = 0.75

Percentage of households having electric irons P(I) = 65% = 0.65

Percentage of households having electric toasters P(T) = 55% = 0.55

Percentage of household having iron and radio P(I∩R) = 50% = 0.5

Percentage of household having radios and toasters P(R∩T) = 40% = 0.40

Percentage of household having iron and toasters P(I∩T) = 30% = 0.30

Percentage of household having all three P(I∩R∩T) = 20% = 0.20

Probability of households having at least one of the appliance can be calculated using the rule:

P(at least one of the three) = P(R) +P(I) + P(T) - P(I∩R) - P(R∩T) - P(I∩T) + P(I∩R∩T)

P(at least one of the three)=0.75 + 0.65 + 0.55 - 0.50 - 0.40 - 0.30 + 0.20  P(at least one of the three) = 0.95

The probability that a household has at least one of these appliances is 0.95

3 0
3 years ago
Algebra help please?
Alika [10]

Ok, basically if you want to find when both equations are equal just make them equal to each other. 0.925x^2 - 4x + 20  = -1.125x^2 + 6x + 40.

From there use algebraic steps to find out what x is ( the break - even point ).

0.925x^2 - 4x + 20 = -1.125x^2 + 6x + 40

0.855625x - 4x + 20 = 1.265625x + 6x + 40

-0.41x - 4x + 20 = 6x + 40

-4.41x + 20 = 6x + 40

20 = 10.41x + 40

-20 = 10.41x

-1.92122958694 = x

Rounded to the nearest tenth it's -1.9 = x.

Tell me if I got something wrong :)

3 0
3 years ago
1360 concert tickets were sold for a total of $13,328. If students paid $8 and non students paid $12, how many student tickets w
lyudmila [28]

748 student tickets were sold.

Step-by-step explanation:

Given,

Number of tickets sold = 1360

Revenue generated = $13328

Cost of each student ticket = $8

Cost of each non student ticket = $12

Let,

x be the number of student tickets sold

y be the number of non student tickets sold

According to given statement;

x+y=1360        Eqn 1

8x+12y=13328    Eqn 2

Multiplying Eqn 1 by 12

12(x+y=1360)\\12x+12y=16320\ \ \ Eqn\ 3

Subtracting Eqn 2 from Eqn 3

(12x+12y)-(8x+12y)=16320-13328\\12x+12y-8x-12y=2992\\4x=2992\\

Dividing both sides by 4

\frac{4x}{4}=\frac{2992}{4}\\x=748

748 student tickets were sold.

Keywords: linear equation, elimination method

Learn more about elimination method at:

  • brainly.com/question/774670
  • brainly.com/question/763150

#LearnwithBrainly

5 0
3 years ago
La C = (F - 32).<br> F =
dmitriy555 [2]

C = (F - 32) then F = C + 32

8 0
4 years ago
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