Answer:
12m
Step-by-step explanation
If the height of the ball after x seconds be modelled by the equation
h(x)=−(x−2)² +16
The height of the ball at the time it is thrown will be the height at the initial time. At that point that it is initially thrown the time is 0seconds i.e x = 0
To get the height at t x = 0seconds, we will substitute x = 0 into the modeled function to have;
h(0) = -(-0-2)²+16.
h(0) = -(-2)²+16
h(0) = -4+16
h(0) = 12
The height of the ball at the time the ball is thrown is 12m
Answer:
Step-by-step explanation:
here is a solution :
Answer:
8.79299999999
Step-by-step explanation:
no se hablar inglés gracias
Answer: y=2/3x+1
Step-by-step explanation:
y=2/3x-6
y=2/3x+b ==> Parallel to y=2/3x-6 since they both have the same slope
3=2/3 (3)+b
3=2*3/3 +b
3=6/3 +b
3=2+b
b=1
y=2/3x+1
Answer:
- 12.4
Step-by-step explanation:
Substitute the given values into the expression
- | 5(- 2) + (- 3) | + | 3(3) + 2(- 4.2) |
= - | - 10 - 3 | + | 9 - 8.4 |
= - | - 13 | + | 0.6 |
= - | 13 | + | 0.6 |
= - 13 + 0.6
= - 12.4
